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AleksandrR [38]
3 years ago
5

Which table represents a linear function?

Mathematics
2 answers:
shutvik [7]3 years ago
6 0
The Last table is linear
a_sh-v [17]3 years ago
3 0

The last table is linear (1/2, 1, 1.5, 2)

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Which inequality is false? A. 4 < 9 B. –6 < –3 C. –5 > –2 D. 12 > –7
CaHeK987 [17]
Simple...

which inequality is false? 

A.) 4<9 (True)

B.) -6<-3 (True)

C.) -5>-2 (False)

D.) 12>-7 (True)

Thus, your answer.
4 0
2 years ago
Read 2 more answers
Help!! help!! help!! help!! help!! help!! help!! help!! help!!
oksian1 [2.3K]

Answer:

<em>(8.21, -20.79)</em>

Step-by-step explanation:

Given the simultaneous equation;

\frac{a}{b} - \frac{b}{2} = 10\\a - b = 29

From 2;

a = 29 + b ....3

Substitute 3 into 1;

\frac{29+b}{b} - \frac{b}{2}  = 10\\\frac{2(29+b)-b^2}{2b} = 10\\\frac{58+2b-b^2}{2b} = 10\\58+2b-b^2 = 20b\\b^2-2b-58 = -20b\\b^2-2b+20b -58 = 0\\b^2+18b-58 = 0\\

Factorize

b = -18±√18²-4(-58)/2

b = -18±√324+232/2

b = -18±√556/2

b = -18±23.58/2

b = -18-23.58/2 and -18+23.58/2

b = -41.58/2 and 5.58/2

b = -20.79 and 2.79

Since a = 29 + b

when b = -20.79

a = 29 - 20.79

a = 8.21

<em>Hence the solution to the system of equation is (8.21, -20.79)</em>

7 0
2 years ago
5.<br> Which picture shows a rotation of the flag?<br> (1)<br> (2)<br> (3)<br> (4)
RUDIKE [14]

Answer:

4 my good sir

Step-by-step explanation:

4 0
2 years ago
What is the value of a?
emmasim [6.3K]

Answer:

A=8

Step-by-step explanation:

If you use the formula 30-60-90 which is a-radical 3a-2a

since the hypotenuse is 2a it equals 16

therefore if its 2a all you need to do is divide it where then you get 8.

6 0
2 years ago
Use Green's Theorem to calculate the circulation of F =2xyi around the rectangle 0≤x≤8, 0≤y≤3, oriented counterclockwise.
Tamiku [17]

Green's theorem says the circulation of \vec F along the rectangle's border C is equal to the integral of the curl of \vec F over the rectangle's interior D.

Given \vec F(x,y)=2xy\,\vec\imath, its curl is the determinant

\det\begin{bmatrix}\frac\partial{\partial x}&\frac\partial{\partial y}\\2xy&0\end{bmatrix}=\dfrac{\partial(0)}{\partial x}-\dfrac{\partial(2xy)}{\partial y}=-2x

So we have

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D-2x\,\mathrm dx\,\mathrm dy=-2\int_0^3\int_0^8x\,\mathrm dx\,\mathrm dy=\boxed{-192}

6 0
3 years ago
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