Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
The correct answer is true because the origin will always be (0,0)
Y - 11 = 3(x + 4)....distribute thru the parenthesis
y - 11 = 3x + 12....add 11 to both sides
y = 3x + 12 + 11...simplify
y = 3x + 23 <==
The answer is 1,230. All you have to do is add everything on the right side you don’t have to worry about anything on the left.
