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Rufina [12.5K]
4 years ago
5

Can someone help struggling please please

Mathematics
1 answer:
ivolga24 [154]4 years ago
5 0

Answer:

I don't know this math sorry!

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Assume that the average life of a refrigerator is 14 years, with the standard deviation given in part (a) before it breaks. Supp
fiasKO [112]

Answer:

The guarantee should be made of X = 1.555 + 14\sigma years, in which \sigma is the standard deviation given in part (a).

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Assume that the average life of a refrigerator is 14 years

This means that \mu = 14

The standard deviation given in part (a) before it breaks.

This will be the value of \sigma

However, the company does not want to replace more than 6% of the refrigerators under guarantee. For how long should the guarantee be made?

We need to find the 100 - 6 = 94th percentile, which is X when Z has a pvalue of 0.94. So X when Z = 1.555. So

Z = \frac{X - \mu}{\sigma}

1.555 = \frac{X - 14}{\sigma}

X = 1.555 + 14\sigma

The guarantee should be made of X = 1.555 + 14\sigma years, in which \sigma is the standard deviation given in part (a).

7 0
3 years ago
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