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3 years ago

PLEASE PLEASE PLEASEE HELP ME!?!!?

2 answers:

7 0

Ans: Option c. "The strongest is strong nuclear, the next strongest is electromagnetism, then weak nuclear, and the weakest is gravitational."

Hope this helps!

Lynna [10]3 years ago

6 0

Answer:

"The strongest is strong nuclear, the next strongest is electromagnetism, then weak nuclear, and the weakest is gravitational."

Explanation:

There are 4 fundamental forces present in the universe.

1. Gravitational force

2. Strong nuclear force

3. Electromagnetic force

4. Weak nuclear force

Strong nuclear force is the strongest force in the universe. It binds quarks together. Electromagnetic force is the second strong force. It acts between electrically charged particles such as protons, neutrons etc. Weak nuclear force is a weaker force which is responsible for particle decay. Gravitational force is the weakest force. It acts between objects having mass.

Hence, the correct option is (c).

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At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci

Klio2033 [76]

Answer:

The radius of a chamber is 2.36 meters.

Explanation:

Given that,

The outer wall moves at a speed of 2.72 m/s.

Mass of the person, m = 75.1 kg

The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :

$F=\dfrac{mv^2}{r}$

r is the radius of a chamber

$r=\dfrac{mv^2}{F}$

$r=\dfrac{75.1\times (2.72)^2}{235}$

r = 2.36 meters

So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.

7 0

3 years ago

Sound Waves....?

Anni [7]

Answer:

longitudinal

Explanation:

because particles of medium through which the sound is transported vibrate parallel to the direction of the sound wave moves

7 0

3 years ago

Read 2 more answers

A force of 44 N will stretch a rubber band 88 cm (0.080.08 m). Assuming that Hooke's law applies, how far will aa 11-N forc

Setler79 [48]

Answer:

The rubber band will be stretched 0.02 m.

The work done in stretching is 0.11 J.

Explanation:

Force 1 = 44 N

extension of rubber band = 0.080 m

Force 2 = 11 N

extension = ?

According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.

F = ke

where k = constant of elasticity

e = extension of the material

F = force applied.

For the first case,

44 = 0.080K

K = 44/0.080 = 550 N/m

For the second situation involving the same rubber band

Force = 11 N

e = 550 N/m

11 = 550e

extension e = 11/550 = 0.02 m

The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch. This is in line with energy conservation.

potential energy stored = $\frac{1}{2}ke^{2}$

==> $\frac{1}{2}* 550* 0.02^{2}$ = 0.11 J

3 0

3 years ago

A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material.

olga2289 [7]

Answer:

True

Explanation:

A coaxial cable is a type of cable that has an inner conductor surrounded by an insulating layer, surrounded by a conductive shielding.

4 0

3 years ago

With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be

jeyben [28]

Question:

Assumptions

Voltage of battery = 24 V

Resistance on the right,20Ω parallel to 10 Ω resistor

Answer:

For the current out of the battery to be the same as when the switch was opened with the switch closed, the resistance on the resistor on the right must be approximately 20/3 Ω

Explanation:

We note that the switch in the assumption is on the same line as the 20 Ω resistor.

With a voltage of 24 V, and the switch closed, we have;

Total resistance = $\frac{1}{\frac{1}{10} +\frac{1}{20} } = \frac{20}{3} \Omega$

Current out of voltage, I = Voltage/(total resistance)

= 24 ÷ 20/3 = 24 × 3/20 = 18/5 A

Therefore, with the switch opened, we get

Resistance on the right = Initial total resistance $= \frac{20}{3} \Omega$

Therefore, with the switch opened, the resistance on the resistor on the right must be approximately equal to the resultant resistance of the two resistances in parallel.

6 0

3 years ago