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3 years ago

ASAP WILL GIVE BRAINLIEST!!!

Physics

1 answer:

Oksana_A [137]3 years ago

5 0

Answer:

The change in momentum of the car is 3575 Kg.m/s

Explanation:

Impulse and Momentum

The impulse (J) experienced by the object equals the change in momentum of the object (Δp).

The formula that represents the above statement is:

J = Δp

The impulse is calculated as

J = F.t

Where F is the applied force and t is the time.

The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:

J = 6500 * 0.55

J = 3575 Kg.m/s

The change in momentum of the car is:

$\Delta p= J = 3575\ Kg.m/s$

The change in momentum of the car is 3575 Kg.m/s

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in which kind of radioactive decay would the number of protons in the resulting nucleus be more than in the initial nucleus?

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3 years ago

An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600

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Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

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4 years ago

Which would you most expect to be an unstable atom?

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3 years ago

Read 2 more answers

A newly discovered particle, the SPARTYON, has a mass 455 times that of an electron. If a SPARTYON at rest absorbs an anti-SPART

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Answer:

υ = 5.62 x 10¹⁴ Hz

Explanation:

The process of of formation of photons takes place due to interaction of a particle with its anti-particle is called Annihilation of Matter. Here SPARTYON absorbs anti-SPARYTON to form 2 photons. Applying conservation of energy to the to this scenario, we get:

2(Energy of Each Photon) = Rest Mass Energy of SPARTYON + Rest Mass Energy of anti-SPARTYON

$2hv = m_{0}c^2 + m_{0}c^2\\\\2hv = 2m_{0}c^2\\\\hv = m_{0}c^2\\\\v = \frac{m_{0}c^2}{h}$

where,

υ = frequency of each photon = ?

m₀ = rest mass of SPARTYON = mass of anti-SPARTYON = 455*Mass of electron

m₀ = 455(9.1 x 10⁻³¹ kg) = 4.14 x 10⁻²⁸ kg

c = speed of light = 3 x 10⁸ m/s

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

Therefore, using these values in the equation, we get:

$v = \frac{(4.14 x 10^{-28} kg)(3 x 10^8 m/s)^2}{6.625 x 10^{-34}J.s}\\\\$

υ = 5.62 x 10¹⁴ Hz

5 0

3 years ago