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1 answer:
Answer:
<em>The change in momentum of the car is 3575 Kg.m/s</em>
Explanation:
<u>Impulse and Momentum</u>
The impulse (J) experienced by the object equals the change in momentum of the object (Δp).
The formula that represents the above statement is:
J = Δp
The impulse is calculated as
J = F.t
Where F is the applied force and t is the time.
The car hits a wall with a force of F=6500 N and stops in 0.55 s. Thus, the impulse is:
J = 6500 * 0.55
J = 3575 Kg.m/s
The change in momentum of the car is:
The change in momentum of the car is 3575 Kg.m/s
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Answer:
U₂ = 20 J
KE₂ = 40 J
v= 12.64 m/s
Explanation:
Given that
H= 12 m
m = 0.5 kg
h= 4 m
The potential energy at position 1
U₁ = m g H
U₁ = 0.5 x 10 x 12 ( take g= 10 m/s²)
U₁ = 60 J
The potential energy at position 2
U₂ = m g h
U ₂= 0.5 x 10 x 4 ( take g= 10 m/s²)
U₂ = 20 J
The kinetic energy at position 1
KE= 0
The kinetic energy at position 2
KE= 1/2 m V²
From energy conservation
U₁+KE₁=U₂+KE₂
By putting the values
60 - 20 = KE₂
KE₂ = 40 J
lets take final velocity is v m/s
KE₂= 1/2 m v²
By putting the values
40 = 1/2 x 0.5 x v²
160 = v²
v= 12.64 m/s
Answer:
-72\times 10^{-19}C[/tex]
Explanation:
Both electron and proton have the same amount of charge but signs are opposite , electron contains negative charge and proton contain positive charge
Charge on 1 electron =
So charge on 206 electron
Charge on 1 proton =
So charge on 161 electron
So charge of the system =