The centripetal acceleration of an object is given by the relation,
where Ac = centripetal acceleration =
R = radius of rotation = 15 m
V = speed of astronaut
Hence,
solving this we get, V = 38.34 m/s
At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci
1 answer:
Answer:
The radius of a chamber is 2.36 meters.
Explanation:
Given that,
The outer wall moves at a speed of 2.72 m/s.
Mass of the person, m = 75.1 kg
The person feels a force of 235 N force pressing against his back. The force acting on the person is centripetal force. It is given by the below formula :
r is the radius of a chamber
r = 2.36 meters
So, the radius of a chamber is 2.36 meters. Hence, this is the required solution.
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The final atmospheric pressure is
Explanation:
Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,
where
p is the gas pressure
V is the volume
The equation can also be rewritten as
where in our problem we have:
is the initial pressure (the atmospheric pressure at sea level)
is the initial volume
is the final pressure
is the final volume
Solving the equation for p2, we find the final pressure:
Learn more about ideal gases:
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Answer:
So coefficient of kinetic friction will be equal to 0.4081
Explanation:
We have given mass of the block m = 0.5 kg
The spring is compressed by length x = 0.2 m
Spring constant of the sprig k = 100 N/m
Blocks moves a horizontal distance of s = 1 m
Work done in stretching the spring is equal to
This energy will be equal to kinetic energy of the block
And this kinetic energy must be equal to work done by the frictional force
So
So coefficient of kinetic friction will be equal to 0.4081