A battery of e.m.f. 10 V is connected to resistance as shown in figure. The potential

The distance between two consecutive nodesof a standing wave is 20.9cm.Thehandgen-erating the pulses moves up and down throughac

irina1246 [14]

Answer:

Velocity, v = 0.239 m/s

Explanation:

Given that,

The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m

The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.

For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.

$\dfrac{\lambda}{2}=0.209\ m\\\\\lambda=0.418\ m$

Frequency is number of cycles per unit time.

$f=\dfrac{2.57}{4.47}\\\\f=0.574\ Hz$

Now we can find the velocity of the wave.

Velocity = frequency × wavelength

v = 0.574 × 0.418

v = 0.239 m/s

So, the velocity of the wave is 0.239 m/s.

4 0

3 years ago

A mass of 2000 kg is raised 2.0 m in 10 seconds. What is the potential energy of the mass at this height?

Kaylis [27]

Gravitational potential energy is defined as the amount of energy an object possesses at a given height above the Earth's surface. The equation for gravitational energy is E = mgh. Here, m is the mass of the object, g is the acceleration due to gravity, and h is the height above the Earth's surface. Hence, the answer is E = 2000kg x 9.81m/s^2 x 2m = 39240 Joules.

4 0

4 years ago

Hii guys!! ~ i've comeback again!! could you please help me with an assignment?? i have a couple of i know questions!! thank you

Nimfa-mama [501]

Answer:

Speed = 10.24 m/s.

Explanation:

<u>Given the following data;</u>

Distance = 100m

Time = 9.77

To find her speed;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the equation;

$Speed = \frac{distance}{time}$

Substituting into the equation, we have;

$Speed = \frac{100}{9.77}$

<em>Speed = 10.24 meter per seconds. </em>

5 0

3 years ago

you are sitting at the center of a large turntable at an amusement park as it is set spinning freely. you decide to crawl toward

larisa [96]

You are sitting at the center of a large turntable at an amusement park as it is set spinning freely. You decide to crawl towards the edge of the turntable. Rotational speed will decrease

There is no external torque

hence , the angular momentum of the table is conserved

L (initial) = L ( final)

since , L = m*v*r

where

m = mass

v = velocity

r = radius

If the person is crawled towards the outer rim, then the rotational inertia of the turntable will increase. In order to conserve the angular momentum , its rotational speed will decrease as mass and radius cannot be altered .

To learn more about torque here :

brainly.com/question/19104073

#SPJ4

7 0

1 year ago

I was having trouble with this problem, and problems like it: A 3.2 kg pelican, with a 1.73 kg fish in its mouth, is flying 1.52

Oduvanchick [21]

Answer:

28.1 m/s

Explanation:

$u_x$ = Initial velocity of the fish = 1.52 m/s

y = Height of the bird = 40 m

$a_y$ = Acceleration in y axis = $9.81\ \text{m/s}^2$

$u_y$ = Initial velocity in y axis = 0

$y=u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 40=0+\dfrac{1}{2}\times 9.81t^2\\\Rightarrow t=\sqrt{\dfrac{40\times 2}{9.81}}\\\Rightarrow t=2.86\ \text{s}$

$v_y=u_y+a_yt\\\Rightarrow v_y=0+9.81\times 2.86\\\Rightarrow v_y=28.057\ \text{m/s}$

The final velocity in x direction will remain the same as the initial velocity as there is no acceleration in the x direction $u_x=v_x=1.52\ \text{m/s}$

Resultant velocity is given by

$v=\sqrt{v_x^2+v_y^2}\\\Rightarrow v=\sqrt{1.52^2+28.057^2}\\\Rightarrow v=28.1\ \text{m/s}$

The fish is moving at a velocity of 28.1 m/s when it hits the water.

6 0

3 years ago