All categories

3 years ago

Use the Empirical Rule to answer each question.

Mathematics

1 answer:

Oliga [24]3 years ago

7 0

Step-by-step explanation:

(a)

the probability of parcels weighing 35oz or less is

0.841

the probability of parcels weighing 14oz or less is

0.023

the probability of parcels weighing between 14 and 35oz is the probabilty of 35oz minus the probability of 14oz

0.841 - 0.023 = 0.818

the percentage is the probability × 100 = 81.8%

(b)

the probability of parcels weighing more than 49oz is 1 minus the probability to weigh less than 49oz.

the probability to weigh less than 49oz is

0.99865

so, the probability to weigh more than 49oz is

1 - 0.99865 = 0.00135

the percentage is again probability×100 = 0.14%

You might be interested in

Find the value of y2=255

Butoxors [25]

Answer:

15.96871942

…

−

15.96871942

…

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A number is between 41 and 46 . it has prime factors of 2 and 11 what is the number

AfilCa [17]

44 because it goes into 2 and also goes into 11

4 0

3 years ago

D divided by 4 plus 12 = 20 show steps what is d

tester [92]

Answer:

d=32!!!

Step-by-step explanation:

So first rewrite it as an equation: d/4+12=20

d/4+12=20 then subtract 12 from both sides to balance the equation

d/4=8 so multply both sides by 4 to isolate the variable, 4(d/4)=d =d and 8x4=32, so d=32

4 0

2 years ago

Read 2 more answers

Julia examines the two triangles below and determines that .

baherus [9]

IN Δ MLN:

∠M = 18.3 , ∠L = 98.6 AND ∠N = 180 - (∠M + ∠L) = 180 - (18.3 + 98.6 ) = 63.1

IN Δ FGH:

∠F = 98.6 , ∠G = 61.1 AND ∠H = 180 - (∠F + ∠G ) = 180 - (98.6 + 61.1 ) = 20.3

∴ ONLY ∠N = ∠F = 98.6

There is no other congruent angles

So, The correct statement is :

Inaccurate. The triangles are not similar because angle M is not congruent to angle H, and angle N is not congruent to angle G.

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=Simplify%3A%20%5Cfrac%7B%205%C3%97%2825%29%5E%7Bn%2B1%7D%20-%2025%20%C3%97%20%285%29%5E%7B2n%7

Katen [24]

$\green{\large\underline{\sf{Solution-}}}$

Given expression is 

$\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} }$

can be rewritten as

$\rm \: = \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\$

And

$\purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\$

So, using this identity, we

$\rm \: = \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} }$

can be further rewritten as

$\rm \: = \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} }$

$\rm \: = \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)}$

$\rm \: = \: \dfrac{4}{25 - 1}$

$\rm \: = \: \dfrac{4}{24}$

$\rm \: = \: \dfrac{1}{6}$

Hence, 

$\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}$

4 0

2 years ago