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lutik1710 [3]
3 years ago
12

HELP Will give brainliest

Mathematics
1 answer:
ad-work [718]3 years ago
4 0

Answer:

i think its 18  hope it helps

Step-by-step explanation:

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Find the area of the shaded triangle
Ivanshal [37]

Answer:

18 square units

Step-by-step explanation:

The square shows you the width and height of the triangle.

The area of any triangle if equal to 0.5 * width * height, so:

0.5 * 6 * 6 = 3 * 6 = 18 square units.

6 0
2 years ago
The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term
Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be 1, 5, and 25.

The sum of the first seven terms of the geometric sequence would be 127.

Step-by-step explanation:

<h3>1.</h3>

Let d denote the common difference of the arithmetic sequence.

Let a_1 denote the first term of the arithmetic sequence. The expression for the nth term of this sequence (where n\! is a positive whole number) would be (a_1 + (n - 1)\, d).

The question states that the first term of this arithmetic sequence is a_1 = 1. Hence:

  • The third term of this arithmetic sequence would be a_1 + (3 - 1)\, d = 1 + 2\, d.
  • The thirteenth term of would be a_1 + (13 - 1)\, d = 1 + 12\, d.

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let r denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d.

Ratio between the third term and the second term of the geometric sequence:

\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}.

Both (1 + 2\, d) and \left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right) are expressions for r, the common ratio of this geometric sequence. Hence, equate these two expressions and solve for d, the common difference of this arithmetic sequence.

\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}.

(1 + 2\, d)^{2} = 1 + 12\, d.

d = 2.

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be 1, (1 + (3 - 1) \times 2) = 5, and (1 + (13 - 1) \times 2) = 25, respectively.

These three terms (1, 5, and 25, respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be r = 25 /5 = 5.

<h3>2.</h3>

Let a_1 and r denote the first term and the common ratio of a geometric sequence. The sum of the first n terms would be:

\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}.

For the geometric sequence in this question, a_1 = 1 and r = 25 / 5 = 5.

Hence, the sum of the first n = 7 terms of this geometric sequence would be:

\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}.

7 0
2 years ago
What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)?<br><br> 3<br> 4<br> 5<br> 9
wolverine [178]
The correct answer is 4

1.5 (4+4) -3 = 9

4.5 ( 4-2) =9
4 0
3 years ago
Read 2 more answers
What is the area of a trapezoid if the base is 5, 17, 7 and height is 4
posledela
The area of the trapezoid would be 48
5 0
3 years ago
Find the mean, median, and mode of the data set. Round your answers to the nearest tenth if necessary.
bekas [8.4K]

Answer:

Mean: 83.2

Median: 82.5

Mode: 72

Step-by-step explanation:

If you put them all in order, Its really straightforward from there.

3 0
3 years ago
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