f(x) = 4^x
f(1) just means we plug 1 in for x.
4^1 = 4
So, f(1) = 4^1 = 4
The equation given is:
![\frac{6}{ a^{2} - 7a+6 }](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B%20a%5E%7B2%7D%20-%207a%2B6%20%7D)
.
The second equation will have x as the unknown equivalent numerator with the denominator as (a-6)(a-1)(a+6).
Simplifying the second equation would result to:
![\frac{x}{(a-6)(a-1)(a+6)} = [tex]\frac{6}{ a^{2} - 7a+6 }](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B%28a-6%29%28a-1%29%28a%2B6%29%7D%20%3D%20%20%5Btex%5D%5Cfrac%7B6%7D%7B%20a%5E%7B2%7D%20-%207a%2B6%20%7D%20)
Equating the two equations:
![\frac{6}{ a^{2} - 7a+6 } = \frac{x}{ (a^{2} - 7a+6) (a+6) } ](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B%20a%5E%7B2%7D%20-%207a%2B6%20%7D%20%3D%20%5Cfrac%7Bx%7D%7B%20%28a%5E%7B2%7D%20-%207a%2B6%29%20%28a%2B6%29%20%7D%20%0A%0A)
x = 6(a+6). The numerator of the equivalent equation is 6(a+6).
Answer:
40 I think
Step-by-step explanation:
75+40x=40 I think