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Virty [35]
4 years ago
13

You have 6 equal parts shade in 2 thirds

Mathematics
1 answer:
Helga [31]4 years ago
7 0
2/3 of 6 parts would be:
2/3=x/6
X=4
So shade 4 of the 6 parts.
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80 POINTS !!!!!! Will give brainliest.
MariettaO [177]

Answer:

Step-by-step explanation:

f(1)=2^1+3=2+3=5

f(5)=2^5+3=32+3=35

rate ~of~change=\frac{f(5)-f(1)}{5-1} =\frac{35-5}{5-1} =\frac{30}{4} =7.5

5 0
4 years ago
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Kirk is getting a raise of 5% due to inflation. His normal salary is 56,000 per year. Which of the following calculations gives
klemol [59]

Answer:

280,000 is your answer

Step-by-step explanation:

3 0
3 years ago
Determine the zero of F(x)=x^2+3x-5
IgorLugansk [536]

Answer:

The answer to your question is:

Step-by-step explanation:

                                             x² + 3x - 5

                                    x² + 3x + (3/2)² = 5 + (3/2)²

                                         (x + 3/2)² = 5 + 9/4

                                         (x + 3/2)² = (20 + 9) /4

                                          (x + 3/2)² = 29/4

                                          x + 3/2 = ±√29 / 2

                                     

x 1 = -3/2 + √29/2                               x2 = -3/2 - √29/2

x1 = 1.19                                                x2 = -4.19

3 0
3 years ago
In this problem we use the change of variables x=5s+tx=5s+t, y=s−ty=s−t to compute the integral ∫r(x+y)da∫r(x+y)da, where rr is
Mazyrski [523]

x=5s+t

y=s-t

The Jacobian matrix for this transformation is

\mathbf J=\dfrac{\partial(x,y)}{\partial(s,t)}=\begin{bmatrix}\dfrac{\partial x}{\partial s}&\dfrac{\partial x}{\partial t}\\\\\dfrac{\partial y}{\partial s}&\dfrac{\partial y}{\partial t}\end{bmatrix}=\begin{bmatrix}5&1\\1&-1\end{bmatrix}\implies\det\mathbf J=-6

The vertices in the x,y plane correspond to the following points in the s,t plane:

(x,y)=(0,0)\implies\begin{cases}5s+t=0\\s-t=0\end{cases}\implies(s,t)=(0,0)

(x,y)=(5,1)\implies\begin{cases}5s+t=5\\s-t=1\end{cases}\implies(s,t)=(1,0)

(x,y)=(6,0)\implies\begin{cases}5s+t=6\\s-t=0\end{cases}\implies(s,t)=(1,1)

(x,y)=(1,-1)\implies\begin{cases}5s+t=1\\s-t=-1\end{cases}\implies(s,t)=(0,1)

That is, the parallelogram \mathcal R is mapped to a square \mathcal R^* in the s,t plane, so

\displaystyle\iint_{\mathcal R}x+y\,\mathrm dA=\iint_{\mathcal R^*}((5s+t)+(s-t))|\det\mathbf J|\,\mathrm ds,\,\mathrm dt

=\displaystyle6\int_{t=0}^{t=1}\int_{s=0}^{s=1}6s\,\mathrm ds\,\mathrm dt=18

6 0
3 years ago
A triangle has two sides of lengths 7 and 12. What value could the length of
Alex73 [517]

Answer:

The length of the third side is 23

Step-by-step explanation:

All check

6 0
3 years ago
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