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3 years ago

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Given the following rectangle and circle, at what approximate value of x are the two areas equal? x ≈ 5.8 x ≈ 3.4 The curves do

not intersect, so there is no solution. x ≈ 8.7

1 answer:

SIZIF [17.4K]3 years ago

6 0

The approximate value of x will be approximately equal to 3.4

<h3>Area of triangle and circle</h3>

The formula for calculating area of rectangle is expressed as:

A = lw

l is the length
w is the width

Ar = (3x-1)(x+2)

Ar = 3x^2+6x-x-2

Ar = 3x^2 + 5x - 2

For the circle

Ac = πr²

Ac = 3.14(x-3)²

Ac = 3.14(x²-6x+9)

Ac = 3.14x² - 18.84x + 28.26

If the area are equal;

3x² + 5x - 2 = 3.14x² - 18.84x + 28.26

3.14x² - 3x² - 5x - 18.84x + 30.26 = 0
0.14x²-23.84x+30.26 = 0

On factorizing the equation, the approximate value of x will be approximately equal to 3.4

Learn more on area of rectangle here; brainly.com/question/25292087

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Please help me thank you

KonstantinChe [14]

Answer:

168m

Step-by-step explanation:

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both triangles = 24

both rectangles on the side = 90

the bottom rectangle = 54

54 + 24 + 90 = 168m

Hopefully this helps you :)

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3 years ago

What makes this equation an exponential function? y=6x+4

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Step-by-step explanation:

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4 years ago

Read 2 more answers

What is the value of x?<br><br> Enter your answer in the box.

denis23 [38]

let's notice that, each angle has an "angle tickmark", indicating that all three angles are equal, thus is an equilateral triangle, since the sides are equal, then

$\bf \stackrel{AC}{4x-30}~~=~~\stackrel{CB}{2x+20}\implies 2x-30=20 \\\\\\ 2x=50\implies x = \cfrac{50}{2}\implies x=25$

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4 years ago

What fraction completes the equation using a like denominator when adding 1/3 + 3/6 ?

pashok25 [27]

Answer:

The answer is 2/6 .

Step-by-step explanation:

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$\frac{1 \times 2}{3 \times 2}$

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3 years ago

Answer the 3 screenshotted questions below. 30 points!

Triss [41]

Answer:

13. $36a^2b^4$ π

14. $16x^3y^4$ π

15. $-\frac{c^3}{4a^7b^3}$

Step-by-step explanation:

13.

A = π * $r^2$

r = $6ab^2$

A = π* $(6ab^2)^2$

A = π * $(6ab^2)(6ab^2)$

A = π * $36a^2b^4$

A = $36a^2b^4$ π

14.

V = π * $r^2$ * h

r = $2x$

h = $4xy^4$

V = π * $(2x)^2$ * $4xy^4$

V = π * $4x^2$ * $4xy^4$

V = π * $16x^3y^4$

V = $16x^3y^4$ π

15. $\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$ = $-\frac{c^3}{4a^7b^3}$

$\frac{3a^{-4}b^2}{-12a^3b^5c^{-3}}$

$\frac{a^{-4}}{-4a^3b^5c^{-3}}$

$\frac{b^2}{-4^{3+4}b^5c^{-3}}$

$\frac{b^2}{-4^7b^5c^{-3}}$

$\frac{1}{-4a^7b^{5-2}c^{-3}}$

$\frac{1}{-4a^7b^3c^{-3}}$

$\frac{c^3}{-4a^7b^3}$

$-\frac{c^3}{4a^7b^3}$

Hope this helps!

3 0

3 years ago