NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by
The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:
Using the quadratic formula, the solution for our problem is
The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have
The root is
Then, the maximum height is
1029.99 meters above sea level.
I=prt
I=1640*0.06*6/12=49.2
A=1640+49.2=1,689.2
7,000 + 200 + 50 + 6 + 0.3 + 0.05
7,256.35
The answer is C. Because the side triangles inner corner is 51 so the inner corner of the big train fled are 129. 129 + 20 equals 149 and 180 - 149 equals 31.
Answer:
Plot (-9,5) then you do rise over run and go down 2 and to the right 3
Step-by-step explanation:
So your points would be (-9,5) and(-6,3)