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3 years ago

13

Pleaseeeeeeee help .......ASAP

1 answer:

fenix001 [56]3 years ago

5 0

Answer:

Option A

Step-by-step explanation:

Given:

Center of circle = (h,k)= (3,8)

Radius = r = 5

The standard form of equation of circle with center and radius is:

$(x-h)^2+(y-k)^2=r^2\\Putting\ the\ values\\(x-3)^2+(y-8)^2=(5)^2\\Simplifying\\x^2+9-6x+y^2+64-16y=25\\x^2+y^2-6x-16y+9+64=25\\x^2+y^2-6x-16y+73=25\\x^2+y^2-6x-16y+73-25=0\\x^2+y^2-6x-16y+48=0$

Therefore, the general form of the equation of circle given is:

$x^2+y^2-6x-16y+48=0$

Hence, option A is correct ..

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Answer:

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2 years ago

Read 2 more answers

Graphs and equations of lines

dmitriy555 [2]

Answer:

a) $y = -\frac{3}{4} x + 5$

b) $y = 6x-18$

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Step-by-step explanation:

a) The slope / gradient is the coefficient of $x$ , so for a) it will be $y=-\frac{3}{4} x + C$ .

C is the y-intercept, so the full equation will be $y = -\frac{3}{4} x + 5$ .

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Now, we have a point on the line and so far, we know the equation is $y=6x+c$ . The coordinates of the point are (2,-6). So now we substitute the y and x values into the equation in order to find C.

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rise = change in y value

run = change in x value

so, the gradient $= \frac{7-3}{4-(-1)} = \frac{4}{5}$

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Again, to find C we substitute any of the coordinates into the equation. I will use (-1,3).

$3 = \frac{4}{5} (-1) +C$

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Marysya12 [62]

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1 year ago