This is really hard, 5 points (its all those three questions in the screenshot)

Mathematics

1 answer:

Aleksandr [31]3 years ago

6 0

Answer:

4. Option: 2

5. 7 inches

Step-by-step explanation:

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Translate (in terms of x) then solve the algebraic equation. When the sum of a number and 2 is subtracted from 13 the result is

Diano4ka-milaya [45]

13 - (x+2) = 8
subtract 13 from both sides
-(x+2) = -5
divide by -1 to get rid of negative
(x+2) = 5
subtract 2 from both sides
x=3

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3 years ago

Refer to scenario 4. assume that the profit equation is $110x1 + $150x2 what is the profit at corner point (0, 30)?

SashulF [63]

If you have the profit formula which is profit (x1, x2) = 110x1 + 150x2, then by substitution of the given point (x1, x2) = (0, 30), you can find the profit at the corner point profit (0.30 ) = 110 (0) + 150 (30) = 4500.Therefore the profit will be $ 4500

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3 years ago

Someone please help me on this I have 5 minutes!

Alla [95]

Answer: A. sqrt of 500.

Step-by-step explanation: If you simplify the sqrt of 500, you will get 10 sqrt of 5

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2 years ago

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$