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3 years ago

Sally has saved one thousand five hundred cents over nine days from selling lemonade how many dollars does sally have?

Mathematics

1 answer:

KonstantinChe [14]3 years ago

5 0

Answer:

she has saved $5 in the last 9 days because she has saved 500 cents the last 9 days there are 100 cents in a dollar which means she has to save $5

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Patrick made a scale drawing of a newly planted hotel the height of the scale drawing is 27 inches what would be the actual heig

Charra [1.4K]

Answer:

0.6858 meters

Step-by-step explanation:

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3 years ago

Read 2 more answers

a large container holds 5 gallons of water. it begins leaking at a constant rate. after 15 minutes, the container has 2 gallons

Scrat [10]

Answer:

1 gallon ever 5 minutes here is the fraction form if you need it for a graph 3/15 or 1/5

Step-by-step explanation:

if there is 3 gallons gone and it is constant then on gallon goes every 5 minutes 15/3=5

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3 years ago

Find the value of x needed to make the equation True. 3/4(20x-8)-3=54

olasank [31]

Answer:

The answer is option B, x = 4.2

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2 years ago

A trough of water is 20 meters in length and its ends are in the shape of an isosceles triangle whose width is 7 meters and heig

Vaselesa [24]

Answer:

a) Depth changing rate of change is $0.24m/min$ , When the water is 6 meters deep

b) The width of the top of the water is changing at a rate of $0.17m/min$ , When the water is 6 meters deep

Step-by-step explanation:

As we can see in the attachment part II, there are similar triangles, so we have the following relation between them $\frac{3.5}{10} =\frac{a}{h}$ , then $a=0.35h$ .

a) As we have that volume is $V=\frac{1}{2} 2ahL=ahL$ , then $V=(0.35h^{2})L$ , so we can derivate it $\frac{dV}{dt}=2(0.35h)L\frac{dh}{dt}$ due to the chain rule, then we clean this expression for $\frac{dh}{dt}=\frac{1}{0.7hL}\frac{dV}{dt}$ and compute with the knowns $\frac{dh}{dt}=\frac{1}{0.7(6m)(20m)}2m^{3}/min=0.24m/min$ , is the depth changing rate of change when the water is 6 meters deep.

b) As the width of the top is $2a=0.7h$ , we can derivate it and obtain $\frac{da}{dt}=0.7\frac{dh}{dt} =0.7*0.24m/min=0.17m/min$ The width of the top of the water is changing, When the water is 6 meters deep at this rate

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3 years ago

Urgent! Two questions! (Pre Calc) (30 points)

mina [271]

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Sin(90 + q) = sin(90)*cos(q) + sin(q)*cos(90)
sin(90 + q) = 1 * cos(q) + sin(q)*0
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You can elimate anything beginning with Cos
You can also eliminate the sin function with a minus between it.

Problem 2
Sin(x) = 1/csc(x) That makes C and D incorrect.
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3 years ago