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4 years ago

How do I evaluate the expression -(p+q)2 /(-6) for p=2 andq=4

1 answer:

3 0

Plug in the values of p and q where you see them in the equation:

-(2+4)2 / (-6) - Distribute the -1
(-2-4)2 / (-6) - Distribute the 2
(-4-8) / (-6) - Subtract what's inside the parenthesis
(-12) / (-6) - Divide
The answer is 2

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Solve the inequality. Graph the solution set and write it in interval notation. .

STALIN [3.7K]

Answer:

-4

Step-by-step explanation:

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3 years ago

If $1600 earned simple interest of $56.24 in 2 months, what was the simple interest rate? The simple interest rate is % (Do not

Fiesta28 [93]

Answer:

$\$21.1$

Step-by-step explanation:

We know that for principal amount P , time period T and rate of interest $R\%$ , simple interest is given by $S.I. = \frac{P\times R\times T}{100}$ .

Here ,

$P=\$1600\\T=2\,\,months=\frac{2}{12}\,\,years=\frac{1}{6}\,\,years\\S.I=\$56.24$

To find : simple interest rate i.e., $R\%$

On putting values of $P\,,\,T\,,\,S.I$ in formula , we get $S.I. = \frac{P\times R\times T}{100}$

$56.24 = \frac{1600\times R\times 1}{600}\\R=\frac{56.24\times 600 }{1600}=\frac{703\times 3}{100}=\$21.09$

Now we need to round off the answer to the nearest tenth .

So, simple interest rate is % = $\$21.09$ = $\$21.1$

8 0

3 years ago

Which expressions are equivalent to the equation below

Irina18 [472]

Answer:

Polynomial Expression.

Step-by-step explanation:

8 0

3 years ago

Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin

katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula $A=P(1+\frac{r}{n})^{nt}$

In this formula A = amount after time t

P = principal amount

r = rate of interest

n = number of times interest gets compounded in a year

t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year $A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 15000(1+.06)^{1}$

$= 15000(1.06)$ = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

$A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}$

$= 20900(1+.06)^{1}$

$= 20900(1.06)=22154$

So the final amount will be $22154.

3 0

3 years ago

Complete the sentence.<br> 7 is 1/10 of

Schach [20]

7 is 1/10 of.. 70, because 10 times 7 is 70 :)

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3 years ago

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