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3 years ago

Divide 630 by 5 using partial quotients

Mathematics

1 answer:

ZanzabumX [31]3 years ago

5 0

630 divided by 5 is 126

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9. (10x2 + 99x – 5) ÷ (x + 10) =

Goryan [66]

Answer:

4045.10

Step-by-step explanation:

6 0

3 years ago

How can N+4/3=1/3,What is the value of N

ivann1987 [24]

N + 4 / 3 = 1 / 3

Multiply both sides by 3 :

3* ( N + 4 / 3 ) = 3 * ( 1 / 3 )

∴

N + 4 = 1

Subtract 4 from both sides:

N + 4 - 4 = 1 - 4

N = - 3

hope this helps !.

8 0

3 years ago

Patrick had $2000 on his financial aid Visa card. He registered for 5 courses this semester and paid the same amount for each co

Oxana [17]

Answer:

$486

Step-by-step explanation:

2000+430=2430 divided by 5 = 486

7 0

3 years ago

What is <br> 1/6 (12x - 24) + 2x

GREYUIT [131]

4x-4
… … … , , , , , ,

7 0

3 years ago

Find the range of p in equation p(x+1) (x-3)=x-4p-2 has no real roots.

Tanya [424]

Answer:

$\displaystyle p > \frac{1}{4}$ .

Step-by-step explanation:

Expand the left-hand side of this equation:

$p\, (x + 1)\, (x - 3) = p\, \left(x^2 - 2\, x - 3\right) = p\, x^2 - 2\, p\, x - 3\, p$ .

Collect the terms, so that this quadratic equation is in the form $a\, x^2 + b\, x+ c = 0$ :

$p\, x^2 - 2\, p\, x - 3\, p = x - 4\, p - 2$ .

$p\, x^2 - (2\, p + 1)\, x + (p + 2) = 0$ .

In this equation:

$a = p$ .
$b = -(2\, p + 1)$ .
$c = p + 2$ .

Calculate the quadratic discriminant of this quadratic equation:

$\begin{aligned}b^2 - 4\, a\, c &= (-(2\, p + 1))^2 - 4\, p\, (p + 2) \\ &= 4\, p^2 + 4\, p + 1 - 4\, p^2- 8\, p = -4\, p + 1\end{aligned}$ .

A quadratic equation has no real root if its quadratic discriminant is less then zero. As a result, this quadratic equation will have no real root when $-4\, p + 1 < 0$ . Solve for the range of $p$ :

$\displaystyle p > \frac{1}{4}$ .

4 0

3 years ago