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ddd [48]
3 years ago
14

Suppose that f(t) is continuous and twice-differentiable for t≥0. Further suppose f″(t)≥9 for all t≥0 and f(0)=f′(0)=0. Using th

e Racetrack Principle, what linear function g(t) can we prove is less than or equal to f′(t) (for t≥0)?
Mathematics
1 answer:
Paha777 [63]3 years ago
5 0
Give me a heart and I'll tell you the answer
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Answer:

i need more information like how much mai biked

Step-by-step explanation:

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3 years ago
Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
3 years ago
A small rug is 36 inches long. Its width is 2/3 of its length. What is the width of the rug in feet? (3ft=1yard)
11111nata11111 [884]
36*(2/3) = 24
answer is 24<span />
6 0
3 years ago
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Xelga [282]
The formula for the volume of a cone is V=(1/3)πr^2h.
To find r (radius) divide the diameter by 2, giving you 2.5 cm.
Plug in the numbers now !
V=(1/3)(3.14)(2.5^2)(9)
V=(1/3)(3.14)(6.25)(9)
V=(1/3)(176.625)
V=58.875
Therefore, the volume of the cone is about 59cm^3 :)
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3 years ago
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Sasha thought of a number. She called her number t. She divided her number by 7, added 23 to the result, and she got 43. What wa
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Answer:

161

Step-by-step explanation:

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3 years ago
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