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coldgirl [10]
2 years ago
12

What are the last three terms of the binomial expansion 32x³ + 80x'y + 80x³y² +

Mathematics
1 answer:
Gnesinka [82]2 years ago
8 0

The last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

<h3>Binomial expansion</h3>

From the question, we are to determine the last three terms of the binomial expansion 32x⁵ + 80x⁴y + 80x³y² + __ + __ + __

The highest power of the expansion is 5

Using the binomial expansion theorem

(m +n)⁵ = m⁵ + 5m⁴n + 10m³n² + 10m²n³ + 5mn⁴ + n⁵

Now, we will determine the values of m and n by comparison

By comparison,

m⁵ = 32x⁵

m⁵ = (2x)⁵

∴ m = 2x

Also,

5m⁴n = 80x⁴y

Divide both sides by 5, to get

m⁴n = 16x⁴y

Put m = 2x into the equation

(2x)⁴n = 16x⁴y

16x⁴n = 16x⁴y

∴ n = y

Thus, the expression being expanded is (2x + y)⁵

By binomial expansion, the expansion of (2x + y)⁵  is

(2x + y)⁵ = (2x)⁵ + 5(2x)⁴y + 10(2x)³(y)² + 10(2x)²(y)³ + 5(2x)(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + (5×16)x⁴y + (10×8)x³(y)² + (10×4)x²(y)³ + (5×2)x(y)⁴ + y⁵

(2x + y)⁵ = 32x⁵ + 80x⁴y + 80x³y² + 40x²y³ + 10xy⁴ + y⁵

Hence, the last three terms of the given binomial expansion are 40x²y³ + 10xy⁴ + y⁵

Learn more on Binomial expansion here: brainly.com/question/13602562

#SPJ1

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Step-by-step explanation:

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2*(8*6+8*2+6*2)\\\\=2*(48+16+12)\\=2*76\\=152(\text{cm}^2)

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Find the 100th term for the sequence. -9,-4, 1, 6, 11, .......
Paraphin [41]

Answer:

486

Step-by-step explanation:

for the 2nd term, add 5 to -9

for the 3rd, add 5 × 2 to -9

for the 4th, add 5 × 3 to -9

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Tanzania [10]
Correct answers are:
(1) <span>28, 141 known cases
(2) 79913.71 known cases after six weeks (round off according to the options given)
(3) After approx. 9 weeks (9.0142 in decimal)

Explanations:
(1) Put x = 0 in given equation
</span><span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(0)
</span>y= 28, 141


(2) Put x = 6 in the given equation:
<span>y= 28, 141 (1.19)^x
</span><span>y= 28, 141 (1.19)^(6)
</span>y= 79913.71

(3) Since
y= 28, 141 (1.19)^x
And y = <span>135,000

</span>135,000 = 28, 141 (1.19)^x
135,000/28, 141 = (1.19)^x

taking "ln" on both sides:
ln(4.797) = ln(1.19)^x

ln(4.797) = xln(1.19)
x = 9.0142 (in weeks)

5 0
3 years ago
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