I think this is false
hope this helps...
To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.
The vector product between the Force and the radius allows us to obtain the torque, in this way,
Therefore the torque on the particle about the origen is 50k
PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,
Therefore the angle between the ratio and the force is 103.88°
Answer:
A T-chart is used comparing two sides of a topic for example pros and cons or cause and effect. A star diagram is used for organizing the characteristics of a single topic, a central space is used for displaying the topic, with each point showing or listing an attribute about the topic.
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Answer:</h2>
d. An object did work on the environment.
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Explanation:</h2>
Work is defined in many contexts. Some of these are;
i. <em>Work is the product of force and displacement</em>. In this case, work done is positive if the force applied on an object or body and the displacement caused by the force are in the same direction. If instead the force and displacement are in opposite direction, then the work done will be negative. If it is the case the force and the displacement are perpendicular to each other, the work done is zero.
ii. In the first law of thermodynamics, the internal energy of a system is the sum of the work done and the heat exchanged between the system and the environment. Therefore, <em>work done is the difference between the internal energy of a system and the heat exchanged between the system and the environment</em>.
In this case, work is said to be positive if work is done by the system (object) on the environment. It is negative if work is done by the environment on the system (object).
Answer:
ni sin theta i = nr sin theta r where theta i is the angle of incidence and theta r the angle of refraction
For nr greater than ni (air to water) theta r must be smaller and the image would be bent towards the normal
