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vichka [17]
3 years ago
7

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

ind the acceleration of the sled? Check all that apply.
The force of gravity must be broken into its parallel and perpendicular components.

Acceleration can be found by dividing the net force by mass. Acceleration can be found by multiplying the net force by mass.

The magnitude of the force components must be multiplied by gravity.

Trigonometry can be used to solve for the magnitude of the force components.

Net force must be found before acceleration can be found.
Physics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

i. The force of gravity must be broken into its parallel and perpendicular components.

ii. Acceleration can be found by dividing the net force by mass.

iv. Trigonometry can be used to solve for the magnitude of the force components.

vi. Net force must be found before acceleration can be found.

Explanation:

Since the force of gravity is a vector quantity, it has both magnitude and direction, then it has both horizontal and vertical components. But it acts always in the vertical direction so that the vertical component holds. While the horizontal component is zero because it does not act in the horizontal direction.

Therefore, the vertical component of the force of gravity must be broken into its parallel and perpendicular components.

Form Newton's second law;

             F = ma

Thus,      

                  a = \frac{F}{m}

So, acceleration can be found by dividing the net force by mass. And the net force must be found before acceleration can be found.

Llana [10]3 years ago
3 0
-The force of gravity must be broken into its parallel and perpendicular components.-Acceleration can be found by dividing the net force by mass.-Trigonometry can be used to solve for the magnitude of the force components.<span>-Net force must be found before acceleration can be found.</span>
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3 years ago
In which of the two situations described is more energy transferred?
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Answer:

More energy is transferred in situation A

Explanation:

Each of the situations are analyzed as follows;

Situation A

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The temperature of the interior of the freezer in which the chocolate is placed = -20 °C

We note that at 0°C, the water in the chocolate freezes

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Where;

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ΔT₁ = The change in temperature from 40 °C to 0°C

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The temperature of the cup of hot chocolate = 90 °C

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E = m×4.184×(90 - 25) = 271.96

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