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vichka [17]
3 years ago
7

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

ind the acceleration of the sled? Check all that apply.
The force of gravity must be broken into its parallel and perpendicular components.

Acceleration can be found by dividing the net force by mass. Acceleration can be found by multiplying the net force by mass.

The magnitude of the force components must be multiplied by gravity.

Trigonometry can be used to solve for the magnitude of the force components.

Net force must be found before acceleration can be found.
Physics
2 answers:
olga55 [171]3 years ago
8 0

Answer:

i. The force of gravity must be broken into its parallel and perpendicular components.

ii. Acceleration can be found by dividing the net force by mass.

iv. Trigonometry can be used to solve for the magnitude of the force components.

vi. Net force must be found before acceleration can be found.

Explanation:

Since the force of gravity is a vector quantity, it has both magnitude and direction, then it has both horizontal and vertical components. But it acts always in the vertical direction so that the vertical component holds. While the horizontal component is zero because it does not act in the horizontal direction.

Therefore, the vertical component of the force of gravity must be broken into its parallel and perpendicular components.

Form Newton's second law;

             F = ma

Thus,      

                  a = \frac{F}{m}

So, acceleration can be found by dividing the net force by mass. And the net force must be found before acceleration can be found.

Llana [10]3 years ago
3 0
-The force of gravity must be broken into its parallel and perpendicular components.-Acceleration can be found by dividing the net force by mass.-Trigonometry can be used to solve for the magnitude of the force components.<span>-Net force must be found before acceleration can be found.</span>
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Anuta_ua [19.1K]

Answer:

acceleration = 0.2 m/s/s

Explanation:

initial velocity u = 14

final velocity v = 20

time = 30

acceleration = ?

v = u + at

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30a = 6

a = 0.2 m/s/s

5 0
2 years ago
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A 2kg mass is moving at 3m/s. What is its kinetic energy?
Illusion [34]
<h2><u>KINETIC ENERGY</u></h2>

<h3>Problem:</h3>

» A 2kg mass is moving at 3m/s. What is its kinetic energy?

<h3>Answer:</h3>
  • \color{hotpink} \bold{9 \: J} \\

— — — — — — — — — —

<h3>Formula:</h3>

To calculate the velocity of a kinetic energy, we can use formula

  • \underline{ \boxed{  \tt KE =  \frac{1}{2} m{v}^{2}  } }

where,

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  • KE is the kinetic energy in J (joules)
  • m is the mass in kg

— — —

Based on the problem, the givens are:

  • KE (Kinetic energy) = ? (unknown)
  • m (mass) = 2 kg
  • v (velocity) = 3 m/s

<h3>Solution:</h3>

To get the velocity, substitute the givens in the formula above then solve.

\:   \: \tt KE =  \frac{1}{2} m{v}^{2}   \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \: \tt \:   KE =  \frac{1}{2} \times  2 \times {(3)}^{2}  \\ \tt  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  KE =  \frac{1}{2}  \times(2\times 9) \\ \tt  KE =  \underline{ \boxed{ \blue{ \tt9 \: J}}}

Therefore, the kinetic energy is 9 Joules.

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2 years ago
According to the theory of a symmetry breaking, at the moment of quark confinement, when the universe was 10-6 seconds old, what
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At the time of quark confinement, when the universe was 10-6 seconds old, there is found to be one additional proton for every billion antiprotons.

<h3>What is quark confinement?</h3>

Note that  one quark is never found on its own but if particles are said to be smashed together and quarks are found, they are said to be like ends of rubber bands that expands.

Hence, At the time of quark confinement, when the universe was 10-6 seconds old, there is found to be one additional proton for every billion antiprotons.

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2 years ago
In 1970, a rocket powered car called Blue Flame achieved a maximum speed of 1.00(10 km/h (278m/s).Suppose the magnitude of the c
sammy [17]

Answer:

Distance traveled during this acceleration will be 6950 m

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Wear have given maximum speed tat will be equal to final speed of the car        v = 278 m/sec

Constant acceleration a=5.56m/sec^2

As the car starts initially starts from rest so initial velocity of the car u = 0 m/sec

From third equation of motion v^2=u^2+2as

Putting all values in equation

278^2=0^2+2\times 5.56\times s

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3 years ago
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Answer:

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F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

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r is the separation between the two charges

In this problem, we have

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r = 4.5 m is their separation

Substituting into the equation, we find

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Moreover, the force is repulsive. In fact, the following rules apply:

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- When two charges have opposite signs, they attract each other

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