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vichka [17]
4 years ago
7

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f

ind the acceleration of the sled? Check all that apply.
The force of gravity must be broken into its parallel and perpendicular components.

Acceleration can be found by dividing the net force by mass. Acceleration can be found by multiplying the net force by mass.

The magnitude of the force components must be multiplied by gravity.

Trigonometry can be used to solve for the magnitude of the force components.

Net force must be found before acceleration can be found.
Physics
2 answers:
olga55 [171]4 years ago
8 0

Answer:

i. The force of gravity must be broken into its parallel and perpendicular components.

ii. Acceleration can be found by dividing the net force by mass.

iv. Trigonometry can be used to solve for the magnitude of the force components.

vi. Net force must be found before acceleration can be found.

Explanation:

Since the force of gravity is a vector quantity, it has both magnitude and direction, then it has both horizontal and vertical components. But it acts always in the vertical direction so that the vertical component holds. While the horizontal component is zero because it does not act in the horizontal direction.

Therefore, the vertical component of the force of gravity must be broken into its parallel and perpendicular components.

Form Newton's second law;

             F = ma

Thus,      

                  a = \frac{F}{m}

So, acceleration can be found by dividing the net force by mass. And the net force must be found before acceleration can be found.

Llana [10]4 years ago
3 0
-The force of gravity must be broken into its parallel and perpendicular components.-Acceleration can be found by dividing the net force by mass.-Trigonometry can be used to solve for the magnitude of the force components.<span>-Net force must be found before acceleration can be found.</span>
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A girl with a mass of 27 kg is playing on a swing. There are three main forces
N76 [4]

The tension in the swing's chain at the bottom of the swing is 178.35 N.

The given parameters:

  • Mass of the girl, m = 27 kg
  • Speed of the girl, v = 3 m/s
  • Radius of the circle, r = 4 m

The tension in the swing's chain at the bottom of the swing is calculated as follows;

T = mg + ma_c\\\\ T= mg + \frac{mv^2}{r} \\\\T = (12 \times 9.8) + (\frac{27 \times 3^2}{4} )\\\\T = 117.6 \ N \ + \ 60.75 \ N\\\\T = 178.35 \ N

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.

Learn more about tension in vertical circle here: brainly.com/question/19904705

3 0
2 years ago
What is the mirror formula for curved mirrors
Reika [66]
The mirror formula for curved mirrors is:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where
f is the focal length of the mirror
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

The sign convention that should be used in order to find the correct values is the following:
- f: positive if the mirror is concave, negative if the mirror is convex
- d_i: positive if the image is real (located on the same side of the object), negative if it is virtual (located on the opposite side of the mirror)

3 0
3 years ago
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Thirty five soccer players were challenged to do as many sit-ups possible in two minutes
Ghella [55]

Answer:

Explanation:

What is the question?

7 0
3 years ago
calculate the time (in years) it would take to send a message to the Galactic Capitol located at the center of our Milky Way gal
Alinara [238K]

Answer:

The total time is \bf{52850~Yr}.

Explanation:

Given:

The distance between Galactic Capitol and Earth is, d = 2.5 \times 10^{20}~m

The speed of light is, c = 3 \times 10^{8}~m/s

The time taken by the message to reach and come back to Earth is given by

t &=& \dfrac{2d}{c}\\~~&=& \dfrac{2(2.5 \times 10^{20}~m)}{3 \times 10^{8}~m/s}\\~~&=& 1.6 \times 10^{12}~s\\~~&=& \dfrac{1.6 \times 10^{12}~s}{(86400 \times 365)~s}~Yr\\~~&\approx& 52849~Yr

In addition they take 1 year to decide to reply.

Thus, the total time is 25850~Yr.

7 0
4 years ago
Consider a 200 g sample of U-238 with decay constant 2.951x10^-16 min^1. Approximately how many disintegrations will occur per m
slamgirl [31]

Answer:

The disintegrations is 5.902\times10^{-17}\ decay /min.

Explanation:

Given that,

Weight of sample = 200 g

Decay constant \lambda=2.951\times10^{-16}\ min^{-1}

We need to calculate the disintegrations

Using formula of disintegrations

\dfrac{dN}{dt}=\lambda N

Where, \lambda = decay constant

N = number of atoms present at time t

Put the value into the formula

\dfrac{dN}{dt}=2.951\times10^{-16}\times200\times10^{-3}

\dfrac{dN}{dt}=5.902\times10^{-17}\ decay /min

Hence, The disintegrations is 5.902\times10^{-17}\ decay /min.

7 0
4 years ago
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