Answer:
0.0016 T
Explanation:
Parameters given:
Diameter of wire = 5 mm = 0.005 m
Radius of wire, R = 0.0025 m
Number of turns, N = 200
Current through the wire, I = 0.10A
The magnitude of the magnetic field is given as:
B = (u₀NI) / (2πR)
Where u = magnetic permeability of free space.
B = (1.257 * 10⁻⁶ * 200 * 0.1) / (2 * π * 0.0025)
B = 0.0016 T
The magnitude of the Magnetic field is 0.0016 T.
Answer:(1)=current (2)=force (3)=magnetic field (4)=reverse
Explanation:When there's a current in The coil. A force act on each side Of The coil. This is because the coil is in a magnetic field, the direction Of The spin would reverse
The answer's 25,000 joules
half m v squared
half 2000, x 5 squared
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