Question

Which of the following systems of inequalities has point D as a solution? Two linear functions f of x equals 3 times x plus 4 and g of x equals negative one half times x minus 5 intersecting at one point, forming an X on the page. A point above the intersection is labeled A. A point to the left of the intersection is labeled B. A point below the intersection is labeled C. A point to the right of the intersections is labeled D. f(x) ≤ 3x + 4 g of x is less than or equal to negative one half times x minus 5 f(x) ≥ 3x + 4 g of x is less than or equal to negative one half times x minus 5 f(x) ≤ 3x + 4 g of x is greater than or equal to negative one half times x minus 5 f(x) ≥ 3x + 4 g of x is greater than or equal to negative one half times x minus 5

Answer 1

Answer:

B) f(x) ≥ 3x + 4

g of x is less than or equal to negative one half times x minus 5

Step-by-step explanation:

From the above graph,  

If point B is the solution of the system of inequalities, then point B must satisfies both inequalities  

We can see from the graph that

Point B is located above (≥) the boundary line for f(x) and is also below (≤) the boundary line for g(x).

So we can say,

Point b satisfies the inequalities

Therefore,  

The system is  

 f(x) ≥ (3x+4)

 g(x) ≤ (-1/2x -5)

Hopes this Helps :)