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GaryK [48]
3 years ago
15

Find the area of the following circle. (Round answer to the nearest hundredth.) d = 15 in area = square inches circumference = i

nches
Mathematics
1 answer:
alisha [4.7K]3 years ago
8 0

Answer:

314.16

Step-by-step explanation:

Since the diameter is 15 and the radius is only half of the diameter the radius is ten. Now the the equation to find area in a circle is 3.14 (or the pi symbol on your calculator) r squared which would mean 3.14*10^2 which would give you your answer

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8/9 to what power equals 64/81
Ierofanga [76]

2nd

Step-by-step explanation:

8/9 to the second power equals to 64/81. Hope this helps!

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3 years ago
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I need help pleeeeeeeeeeeeeease
dsp73

Answer:

Tj hit 85% of the balls pitched to him

Step-by-step explanation:

6 0
3 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Factor the expression 49b²-36​
Travka [436]

Answer:

49b² - 36

Step-by-step explanation:

Find the factors of 49 & 36:

49 = 1, 7, 49

36 = 1, 2, 6, 18, 36

As you can tell, there are no common factors (1 does not count), therefore, the expression given is already in most factored form.

49b² - 36 is your answer.

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7 0
2 years ago
What does 1/10 of 3000 equal?
arsen [322]
Answer:-
1/10×3000
=300
4 0
2 years ago
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