30 ounces = how many pounds and ounces
1 answer:
Answer: " 1 lb , 14 oz. " .
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Step-by-step explanation:
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Note the exact conversion: " 16 oz. = 1 lb. " .
→ {that is: " 16 ounces = 1 pound " .}.
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30 oz. * ( 1 lb / 16 oz). = lbs. ;
= (30/2) / (16/2) lbs.
= (15 / 8) lbs. ;
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1
8 ┌ 15
<u> - 8 </u>
7 ;
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The answer is equal to: " 1 7/8 lbs. " .
→ (1 lb) + (7/8) (lb). ;
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→ (7/8) lb. = how many "oz." ??
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Note the exact conversion: " 1 lb. = 16 oz. " .
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→ *
;
= oz. ;
→ The "8" cancels to a "1" ; and the "16" cancels to a "2" ;
→ {since: " {16 ÷ 8 = 2 } " ;
and: {since: " {8 ÷ 8 = 1 } " .
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→ So we can rewrite as:
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→ oz. ;
= { 7 * 2 } oz. ;
= 14 oz.
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→ So:
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→ " 30 oz. " = " (1 lb) + (7/8) lb. " ;
= " 1 lb. + 14 oz. " ;
= " 1 lb , 14 oz. " .
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→ The answer is: " 1 lb , 14 oz. " .
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Let us check our answer:
→ Does: " 1 lb. + 14 oz. = ? 30 oz. ? " ;
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Note the exact conversion: " 1 lb. = 16 oz. " .
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→ Does: " 16 oz. + 14 oz. = ? 30 oz. ?? " ;
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₁
16 oz
<u>+ 14 oz </u>
30 oz.
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→ Does: " 30 oz. = ? 30 oz. ? " ??? ; → Yes!
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Hope this helps!
Best wishes to you in your academic endeavors
— and within the "Brainly" community!
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Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π and cos A = cos B · cos C
scratchwork:
A + B + C = π
A = π - (B + C)
cos A = cos [π - (B + C)] Apply cos
= - cos (B + C) Simplify
= -(cos B · cos C - sin B · sin C) Sum Identity
= sin B · sin C - cos B · cos C Simplify
cos B · cos C = sin B · sin C - cos B · cos C Substitution
2cos B · cos C = sin B · sin C Addition
Division
2 = tan B · tan C
<u>Proof LHS → RHS</u>
Given: A + B + C = π
Subtraction: A = π - (B + C)
Apply tan: tan A = tan(π - (B + C))
Simplify: = - tan (B + C)
Substitution: = -(tan B + tan C)/(1 - 2)
Simplify: = -(tan B + tan C)/-1
= tan B + tan C
LHS = RHS: tan B + tan C = tan B + tan C
