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levacccp [35]
3 years ago
11

A class committee is to be made that consists of 2 freshmen, 2 sophomores, 3 juniors, and 3 seniors. If students are being rando

mly chosen from groups of 12 freshmen, 17 sophomores, 16 juniors, and 20 seniors, how many possible committees can be formed?
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Freshmen: ₁₂C₂ \frac{12!}{2!(12 - 2)!} = \frac{12!}{2!*10!} = \frac{12 * 11 * 10!}{2*10!} = \frac{12 * 11}{2} = 6 * 11 = 66

Sophomore: ₁₇C₂  = \frac{17!}{2!(17 - 2)!} = \frac{17!}{2!*15!} = \frac{17 * 16 * 15!}{2 * 15!} = \frac{17 * 16}{2}  = 17 * 8 = 136

Juniors: ₁₆C₃ = \frac{16!}{3!(16 - 3)!} = \frac{16!}{3!*13!} = \frac{16 * 15 * 14 * 13!}{3 * 2 * 13!} = \frac{16 * 15 * 14}{2 * 3} = 8 * 5 * 14 = 560

Seniors: ₂₀C₃ = \frac{20!}{3!(20 - 3)!} = \frac{20!}{3!*17!} = \frac{20 * 19 * 18 * 17!}{3*2*17!} = \frac{20 * 19 * 18}{2 * 3} = 10 * 19 * 6 = 1140

₁₂C₂ * ₁₇C₂  * ₁₆C₃  * ₂₀C₃

66  * 136 *  560 * 1140 = 5,730,278,400

Answer: 5,730,278,400

GuDViN [60]3 years ago
6 0

C(12,2)\cdotC(17,2)\cdotC(16,3)\cdotC(20,3)=\\\\\dfrac{12!}{2!10!}\cdot\dfrac{17!}{2!15!}\cdot\dfrac{16!}{3!13!}\cdot\dfrac{20!}{3!17!}=\\\\\dfrac{11\cdot12}{2}\cdot\dfrac{16\cdot17}{2}\cdot\dfrac{14\cdot15\cdot16}{2\cdot3}+\dfrac{18\cdot19\cdot20}{2\cdot3}=\\\\66\cdot136\cdot560\cdot1140=5,730,278,400

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The decimal value of 4/11 is 0.36 repeating.
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What is the remandier to 92931 divided by 13?
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X^2 - y^2 = 100
luda_lava [24]

Answer:

20

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

x+y=5

Subtract y from both sides:

x=5-y

Now, substitute "5-y" for "x" in the first equation:

(5-y)^2-y^2=100

Note that:

(a-b)^2=a^2-2ab+b^2

25-10y+y^2-y^2=100

Cancel out like terms:

25-10y=100

Subtract 25 from both sides:

-10y=75

Divide both sides by -10

y=\frac{75}{-10}=\frac{15}{-2}=-\frac{15}{2}

Now, substitute this value back into either of the equations to solve for x.

x+y=5\\x-\frac{15}{2}=5\\

Add 15/2 to both sides:

x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}

Now, find the difference:

x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20

8 0
2 years ago
A researcher was interested in utilities provided by city governments. The researcher randomly selected 20 counties from a list
DaniilM [7]

Answer:

1. The population of interest is all city goverments in the U.S.

5. The parameter of interest is the proportion of the city goverments in the U.S. that provide electricity to their residents.

Step-by-step explanation:

Hello!

Missing questions:

Which of the following is true? Select all that apply.

  1. The population of interest is all city governments in the U.S.
  2. The population of interest is the 192 cities.
  3. The population of interest is all city governments that provide utilities to their residents.
  4. The population of interest is 6.25%
  5. The parameter of interest is the proportion of the city governments in the U.S. that provide electricity to their residents.
  6. The parameter of interest is 6.25%
  7. The population of interest is the 20 counties.
  8. The parameter of interest is the list of all counties in the U.S.

The objective of this essay is to test utilities provided by city governments, for this a sample of 20 counties was taken then contacted each city of them counting how many of them provided utilities to their residents, finding out that 12 out of 192 cities (6.25%) provided electricity to their residents.

The study variable is:

X: Number of city governments that provide utilities (electricity) to their residents, in a sample of 192.

The population of the study is the city governments in the U.S.

And the parameter of interest is the population proportion of city governments in the U.S. that provide electricity to their residents.

I hope it helps!

4 0
2 years ago
The total length of wires a b and c is 445 cm wire a is 45 cm longer then wire b and wire b is half as long as wire c how long i
Oksana_A [137]

Answer:

a = 145\ cm

Step-by-step explanation:

Given

a + b + c = 445

a = 45 + b

b = \frac{1}{2}c

Required

Determine the length of a

Solve for c in b = \frac{1}{2}c

2 * b = \frac{1}{2}c * 2

2b  = c

c = 2b

Substitute c = 2b and a = 45 + b in a + b + c = 445

a + b + c = 445

45 + b + b + 2b = 445

45 + 4b = 445

Solve for 4b

4b = 445 - 45

4b = 400

Solve for b

b = 400/4

b = 100

Recall that: a = 45 + b

a=45+100

a = 145\ cm

6 0
3 years ago
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