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3 years ago

7

Felix has 715 baseball cards. He puts them in 25 piles. How many cards are in each pile?

2 answers:

Helen [10]3 years ago

8 0

715 divided by 25 = 28.6 cards in each pile

If this helped make sure to mark as the brainliest!
-procklown

Dmitry_Shevchenko [17]3 years ago

5 0

28.6 but you need to round up to 29

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4th out of 10 questions

lisabon 2012 [21]

(9, 15) since when you multiply them by 3 both values are equivalent.

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3 years ago

What is 5.027 + 4.68r if r= 0.034m

sattari [20]

$5.027+4.68r\\\\r=0.034m\\\\5.027+4.68(0.034m)\\\\\\5.027+(.15912m)$

6 0

4 years ago

Find the magnitude of the net electric field at the origin (created by charges q1 and q2).

Readme [11.4K]

The direction of the net magnetic field is $167.36^{\circ}$

<h3>How to find the magnitude?</h3>

$q_1=-4 \mathrm{nC} \text { at }(0.6,0.8)$

$q_2=6 \mathrm{nC}$ at (0.6,0)

$r_1=$ Distance of $q_1$ from origin $=\sqrt{0.6^2+0.8^2}$

$r_2=$ Distance of $q_2$ from origin $=0.6$

$\mathrm{k}=$ Coulomb constant $$=9$ times $10^9 \mathrm{Nm}^2 / \mathrm{C}^2$$

Electric field is given by

$&E_1=\frac{k q_1}{r_1^2} \\$

$&\Rightarrow E_1=\frac{9 \times 10^9 \times 4 \times 10^{-9}}{\sqrt{0.6^2+0.8^2}} \\$

$&\Rightarrow E_1=36 \mathrm{~N} / \mathrm{C}$

$&\theta=\tan ^{-1} \frac{0.8}{0.6} \\$

$&\Rightarrow \theta=53.13^{\circ} \\$

$&E_1=36 \cos 53.13^{\circ} \hat{i}+36 \sin 53.13^{\circ} \hat{j} \\$

$&\Rightarrow E_1=21.6 \hat{i}+28.8 \hat{j}$

$&E_2=\frac{k q_2}{r_2^2} \\$

$&\Rightarrow E_2=\frac{9 \times 10^9 \times 6 \times 10^{-9}}{0.6^2} \\$

$&\Rightarrow E_2=150 \mathrm{~N} / \mathrm{C}$

The charge $q_2$ is on the $\mathrm{x}$ axis itself and it is pointing towards the origin (left side) so the sign will be negative

$E_2=-150 \hat{i}$

Resultant electric field

$&E=E_1+E_2 \\$

$&\Rightarrow E=21.6 \hat{i}+28.8 \hat{j}+(-150 \hat{i}) \\$

$&\Rightarrow E=-128.4 \hat{i}+28.8 \hat{j}$

Magnitude of electric field is given by

$&|E|=\sqrt{(-128.4)^2+28.8^2} \\$

$&\Rightarrow|E|=121.6 \mathrm{~N} / \mathrm{C}$

Magnitude of the net electric field is $121.6 \mathrm{~N} / \mathrm{C}$

Direction is given by

$\theta=\tan ^{-1} \frac{128.4}{28.8}=77.36^{\circ}$

From the -x axis

$(90+77.36)^{\circ}=167.36^{\circ}$

The direction of the net magnetic field is $167.36^{\circ}$

To learn more about magnetic field, refer to:

brainly.com/question/26257705

#SPJ4

6 0

2 years ago

A mixture contains 1/16 pound sand and 7/8 pound compost. At that rate, what amount of sand is needed if the mixture contains 1

daser333 [38]

Answer:

A. ¹/₁₄ lb

Step-by-step explanation:

¹/₁₆ lb sand goes with ⅞ lb compost.

For 1 lb compost, the mass of sand needed is:

1 lb compost × (¹/₁₆ lb sand)/(⅞ lb compost).

We must evaluate the fraction (¹/₁₆)/(⅞).

Invert the denominator and multiply

(¹/₁₆)/(⅞) = ¹/₁₆ × ⁸/₇ Cancel the 8s

= ½ × ⅐ Multiply numerators and denominators

= ¹/₁₄

For 1 lb of compost, the mass of sand needed is ¹/₁₄ lb.

8 0

4 years ago

What is 49/30 in simplest form?

Verdich [7]

The answer would most likely be 1 19/30

7 0

3 years ago