Answer:
∠BAD=20°20'
∠ADB=34°90'
Step-by-step explanation:
AB is tangent to the circle k(O), then AB⊥BO. If the measure of arc BD is 110°20', then central angle ∠BOD=110°20'.
Consider isosceles triangle BOD (BO=OD=radius of the circle). Angles adjacent to the base BD are equal, so ∠DBO=∠BDO. The sum of all triangle's angles is 180°, thus
∠BOD+∠BDO+∠DBO=180°
∠BDO+∠DBO=180°-110°20'=69°80'
∠BDO=∠DBO=34°90'
So ∠ADB=34°90'
Angles BOD and BOA are supplementary (add up to 180°), so
∠BOA=180°-110°20'=69°80'
In right triangle ABO,
∠ABO+∠BOA+∠OAB=180°
90°+69°80'+∠OAB=180°
∠OAB=180°-90°-69°80'
∠OAB=20°20'
So, ∠BAD=20°20'
Answer:
it's A. sorry for the late answer
Answer:
71
Step-by-step explanation:
vertical sides are congruent
x+30=101
x=71
1.
A. (49-8)*2-16, 41*2-16, 82-16, 66, yep
B. 49-8*-14, 49+112, 161, nope
C. 7^(-16)-16, (1/(7^16))-16, nope
D. 49-16-16, 17, nope
A is answer
2.
2((a+b)²-b)
2((7+1)²-1)
2((8)²-1)
2(64-1)
2(63)
126
C is answer
4.
none of the options give the answer
Answer:
0.22 per
Step-by-step explanation: