<u>Part 1)</u> Find m∠EAD
we know that
m∠EAD+m∠DAF+m∠BAF=
----> by supplementary angles
solve for m∠EAD
m∠EAD=-(m∠DAF+m∠BAF)
in this problem we have
m∠DAF=
m∠BAF=
substitute in the formula above
m∠EAD=
therefore
<u>the answer part 1) is </u>
m∠EAD=
<u>Part 2)</u> Find m∠CAB
we know that
m∠CAB+m∠BAF= --------> by supplementary angles
solve for m∠CAB
m∠CAB=-m∠BAF
in this problem we have
m∠BAF=
substitute in the formula above
m∠CAB=
therefore
<u>the answer part 2) is</u>
m∠CAB=
The bacteria at the end of 22 hours is 2,480
Answer:
6,750,000 cm³ = 6.75 m³
Step-by-step explanation:
a scale version means that the ratio of every dimension of scale vs. real object is 1/50.
volume is created by multiplying 3 dimensions.
so, going from scaling to real the volume has to be multiplied by 50×50×50 = 50³ = 125000
so, as for the scale model we needed 54 cm³, for the full size object we need 54×125000 = 6,750,000 cm³ of metal.
or to bring it to m³ (1m³ = 100×100×100 cm = 1000000 cm³)
that would be 6.75 m³ of metal.
The answer is D i believe
2160
Explanation:
Use the equation (n-2)180
(14-2)180
(12)180
2160
