Question

The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.

Answer 1

Answer:

0.59375

Step-by-step explanation:

In a uniform distribution the probability that the time t is greater than any given value, X, is:

$P(t\geq X)=1-\frac{X}{b-a}$

In this problem, the limits of the distribution are a = 0 and b = 8 minutes.

For X =3.25 minutes:

$P(t\geq 3.25)=1-\frac{3.25}{8-0} \\P(t\geq 3.25)=0.59375$

The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.