Let
x-----------> first <span>odd integer
x+2--------> second consecutive odd integer
x+4-------> third consecutive odd integer
we know that
(x+4)</span>²=15+x²+(x+2)²-------> x²+8x+16=15+x²+x²+4x+4
x²+8x+16=19+2x²+4x-------> x²-4x+3
x²-4x+3=0
using a graph tool----------> to calculate the quadratic equation
see the attached figure
the solution is
x=1
x=3
the answer is
the first odd integer x is 1
the second consecutive odd integer x+2 is 3
the third consecutive odd integer x+4 is 5
The answers is D 21,000because you have to do 60,000x.35=21,000
This isn't the same problem but it's an idea. of what you're doing.
Answer:
<h3>22.627417</h3>
Step-by-step explanation:
![\frac{32}{ \sqrt[8]{16} } \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B32%7D%7B%20%5Csqrt%5B8%5D%7B16%7D%20%7D%20%20%5C%5C%20)
Simplify

Method 2 :
By rationalizing the denominator