Jason has five equally massed lead fishing weights, each weighing 250 grams. What is the total mass of the five leaf fishing wei
1 answer:
Answer:
Total mass of 5 lead fishing weights= 1250 grams
Explanation:
Given:
Mass of a lead fishing weight =250 grams
To find total mass of 5 such fishing weights
We can apply unitary method to find total mass of 5 fishing weights.
If mass of 1 lead fishing weight = 250 grams
∴ Total mass of 5 lead fishing weights =
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Explanation:
a)
oxidation state of H = +1
Oxidation state of O = -2
Let the oxidation no. of S be x.
Oxidation state of S in = +6
b)
oxidation state of H = +1
Oxidation state of O = -2
Let the oxidation no. of Ca be x.
Oxidation state of Ca in = +2
c) BrOH
oxidation state of H = +1
Oxidation state of O = -2
Let the oxidation no. of Br be x.
Oxidation no. of Br in BrOH is +1
d)
oxidation state of Cl = -1
Oxidation state of O = -2
Let the oxidation no. of N be x.
Oxidation state of N in = +3
e)
oxidation state of Cl = -1
Let the oxidation no. of Ti be x.
Oxidation state of Ti in = +4
f) NaH
Na is more electropositive than H.
Therefore, oxidation state of Na = +1
Oxidation state of H = -1