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koban [17]
3 years ago
11

1. What is the value of h? (1 point)

Mathematics
1 answer:
irinina [24]3 years ago
7 0

The value of h is 11.3.

Solution:

Given data:

The triangle is a right triangle.

θ = 45° and opposite side of θ = 8

The value of sin 45° = \frac{1}{\sqrt{2} }

Using trigonometric formula,

$\sin\theta=\frac{\text{Opposite side}}{\text{Hypotenuse}}

$\sin45^\circ=\frac{{8}}{h}

$\frac{1}{\sqrt{2} } =\frac{{8}}{h}

Do cross multiplication.

h = 8\sqrt 2

h = 11.3

The value of h is 11.3.

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In an Algebra II class with 135 students, the final exam scores have a mean of 72.3 and standard deviation 6.5. The exams on the
gregori [183]
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5

Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students

Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students

Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68

Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
4 0
3 years ago
Henry spent 7 6/9 hours working on his reading and math homework.If he spent 6 7/8 on his reading homework,how much time did he
jeyben [28]
GCM of 8 and 9 is 72

6/9 = 64/72
7/8 = 63/72


1 1/72
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How many 1/2 foot pieces can be cut from 6 foot ribbon?
MatroZZZ [7]
Number of ribbons that can be cut = 6 ÷ 1/2 
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Number of ribbons that can be cut = 12 

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Answer: 12  1/2 foot pieces can be cut from 6 feet ribbon
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What is the value of the expression when b=4
shusha [124]
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