How to find a pvalue

What is the volume of the sphere that has a diameter of 3? use 3.14 for pie

aev [14]

Hey ! there

Answer:

113.04 unit cube

Step-by-step explanation:

In this question we are provided with a sphere having radius 3 units and value of π is 3.14 . And we're asked to find the volume of sphere .

For finding volume of sphere , we need to know its formula . So ,

$\qquad \qquad \: \underline{\boxed{ \frak{Volume_{(Sphere)} = \dfrac{4}{3} \pi r {}^{3} }}}$

Where ,

π refers to 3.14

r refers to radius of sphere

Solution : -

Now , we are substituting value of π and radius in the formula ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times (3) {}^{3}$

Simplifying it ,

$\quad \longrightarrow \qquad \: \dfrac{4}{3} \times 3.14 \times 3 \times 3 \times 3$

Cancelling 3 with 3 :

$\quad \longrightarrow \qquad \: \dfrac{4}{ \cancel{3}} \times 3.14 \times 3 \times 3 \times \cancel{3}$

We get ,

$\quad \longrightarrow \qquad \:4 \times 3.14 \times 9$

Multiplying 4 and 3.14 :

$\quad \longrightarrow \qquad \:12.56 \times 9$

Multiplying 12.56 and 9 :

$\quad \longrightarrow \qquad \: \pink{\underline{\boxed{\frak{113.04 \: unit \: cube}}}} \quad \bigstar$

Henceforth , volume of sphere having radius 3 units is 113 .04 units cube .

<h2>#Keep Learning</h2>

5 0

2 years ago

The graph of a bicycle ramp contains the points (-6,0) and (3,3). What is the slope of the ramp?

olasank [31]

The slope of the ramp would be 5/9

7 0

3 years ago

Distance between points (1,2) (4,3)

GREYUIT [131]

Answer:

3.1

Step-by-step explanation:

5 0

3 years ago

What is the area of the composite figure? (6π 4) cm2 (6π 16) cm2 (12π 4) cm2 (12π 16) cm2

raketka [301]

The area of the considered composite figure is given by: Option: 6π + 16 cm²

<h3>How to calculate the surface area of a composite figure?</h3>

Surface area are derived for some standard shapes like circle, triangle, parallelogram, rectangle, trapezoid, etc.

When some shape comes which isn't standard figure, then we find its area by slicing it (virtually, like by drawing lines) in standard shapes. Then we calculate those composing shapes' area and sum them all.

Thus, we have:

$\text{Area of composite figure} = \sum (\text{Area of composing figures})$

That ∑ sign shows "sum"

For this case, the missing image is attached below.

As visible, the area of the figure = Sum of area of those 3 semi circles + Area of that square(its square because it has 4 equal sides in which adjacent sides are perpendicular) in between.

The side of the square is of 2+2=4 cm( as half of its side is 2 cm), thus, Area of that square = 4² = 16 cm²

All those 3 semicircles has radius = 2 cm

Since radius is same, so area of those 3 semicircle is same = $\dfrac{\pi r^2}{2} = \dfrac{\pi (2)^2}{2} = 2 \pi\: \rm cm^2$