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murzikaleks [220]
3 years ago
12

Omar is making a scale model of the Statue of Liberty for a report on New York . The Statue of Liberty is 305 feet tall measurin

g from the ground to the tip of the torch . If the model is 1/100 the actual size of the Statue of Liberty , how tall is the model?
Mathematics
2 answers:
Romashka [77]3 years ago
6 0
305×1/100=305/100= 3.05 feet tall
sattari [20]3 years ago
4 0

The Statue of Liberty is 305 feet tall measuring from the ground to the tip of the torch . If the model is 1/100 the actual size of the Statue of Liberty

Actual size of the statue = 305

Model is \frac{1}{100} of the actual size of the Statue of Liberty

Height of model =  \frac{1}{100} of the actual size

=  \frac{1}{100} * 305

=  \frac{305}{100}= 3.05

Model of Statue of Liberty is 3.05 feet tall


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The equation for this is (n-2) x 180

Replace n with the number of sides:

a. 9:  (9-2) x 180 = 7 x 180 = 1,260

b. 19: (19-2) x 180 = 17 x 180 = 3,060

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Charlie bought hamburgers and drinks for his coworkers. Each hamburger cost $3.75 and each drink cost 50 cents. In total, Charli
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Differentiate Functions of Other Bases In Exercise, find the derivative of the function.
WARRIOR [948]

Answer:

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

Step-by-step explanation:

given

y = \log_{10}{(x^2+6x)}

using the property of log \log_ab=\frac{log_cb}{log_ca}, and if c =e,\log_ab=\frac{ln{b}}{ln{a}}, we can rewrite our function as:

y = \dfrac{\ln{\left (x^{2} + 6 x \right )}}{\ln{\left (10 \right )}}

now we can easily differentiate:

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{d}{dx}(\ln{(x^{2} + 6x)})\right)

\dfrac{dy}{dx} = \dfrac{1}{\ln{10}}\left(\dfrac{2x+6}{x^{2} + 6x}\right)

\dfrac{dy}{dx} =\dfrac{2 x + 6}{ \log{\left (10 \right )}\left(x^{2} + 6 x\right)}

This is our answer!

3 0
3 years ago
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Find the equation of the line that passes through the following two points: (3, -7) and (7, 2)
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Answer:

y=\frac{9}{4}x-\frac{55}{4}

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (3, -7), (7, 2)

(3, -7) = (x1, y1)

(7, 2) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the slope formula:

\frac{2-(-7)}{7-3}

Simplify:

2 - (-7) = 2 + 7 = 9

7 - 3 = 4

\frac{9}{4}

The slope is \frac{9}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (7, 2)) into the equation and solve for b:

2=\frac{9}{4}(7)+b

2=\frac{63}{4}+b

-\frac{55}{4} =b

The y-intercept is -\frac{55}{4}.

Now that we know the slope and the y-intercept, we can write the equation:

y=\frac{9}{4}x-\frac{55}{4}

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Answer: It depends on what categories your teacher has and what percent of your grade it is worth. I would recommend an online grade calculator

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2 years ago
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