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2 years ago

How many one-third cubes are needed to fill the gap in the prism shown below?

Mathematics

2 answers:

attashe74 [19]2 years ago

8 0

Answer:

The answer is 16 I've seen this before so I would know. and your welcome

Step-by-step explanation:

posledela2 years ago

3 0

Answer:

Step-by-step explanation:

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Sally is making a painting for which she is mixing red paint and blue paint. The table above shows the different mixtures being

aleksandr82 [10.1K]

1 1/2 - 2 1/2 is 3/2:5/2 or a 3:5 ratio
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1.2- 2 if divided by .4 is a 3:5 ratio
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8 0

2 years ago

Read 2 more answers

NEED HELP ASAP!!!!!!!

sertanlavr [38]

ANSWER: x > -6
1. subtract 12 from each side
2. divide by -3 which will make the sign flip

8 0

2 years ago

Is the answer 104????? like i multiplied 26 four times but idk if that's what you're supposed to do

jeka94

Answer:

Yes, The answer is 104.

5 0

2 years ago

Which number is a factor of 14, but not a multiple of 2?

bonufazy [111]

7 is a factor of 14 and is not a multiple of 2.

5 0

2 years ago

Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$

Thus the solution becomes

$\tfrac{y}{x^{2}}=\int \frac{1}{x^{2}}\times x^{2}dx\\\\\tfrac{y}{x^{2}}=\int 1dx\\\\\tfrac{y}{x^{2}}=x+c$ $y=x^{3}+cx^{2$

This is the general solution now to find the particular solution we put value of x=2 for which y=6

we have $6=8+4c$

Thus solving for c we get c = -1/2

Thus particular solution becomes

$y=x^{3}-\frac{1}{2}x^{2}$

5 0

3 years ago