Someone help pls for number 59
2 answers:
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Answer:
A) increase.
Explanation:
- By definition, the capacitance of a capacitor, is the charge on one of the plates, divided by the potential difference between them, as follows:
- At the same time, we can show (applying Gauss' Law to the surface of one of the plates), that the capacitance of a parallel-plate capacitor (with a dielectric of air), can be written as follows:
C = ε₀*A / d (2)
- If the space between plates, is filled with a dielectric of dielectric constant κ, the above equation becomes:
- If the capacitor, once charged, is disconnected from the battery, charge must keep the same.
- Now, if we remove the dielectric, as stated in (3) and (2), the capacitance C will decrease when removing the dielectric.
- From (1) if C decreases, and Q remains constant, in order to keep both sides of the equation equal each other, V (the potential difference between plates), must increase.
The final velocity is 3.47 m/s east
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the two players before and after the collision must be conserved:
where:
is the mass of the first player
is the initial velocity of the first player (we take east as positive direction)
is the mass of the second player
is the initial velocity of the second player
is their final combined velocity after the collision
Re-arranging the equation and substituting the values, we find:
So, their velocity afterwards is 3.47 m/s east.
Learn more about momentum:
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