Answer:
a) x=11.15m
b) y= 5.6m
Explanation:
This is the given data:
t1=4.5s t2=11.7s
V1=3.5 (j)m/s V2=-3.5 (i)m/s
a1 = a(i) a2 = a(j)
r1 = 5.8(i)+5.6(j) m
From this data we conclude that the orbit is as the one shown in the picture.
So, the position of the center will be rc = r1 + R(i) = (5.8+R)(i) + 5.6(j)
Calculating the distance traveled by the particle:
S = V*Δt = 3.5 * (11.7-4.5) = 25.2m
Since S = θ * R and from the picture we know that θ = 3π/2
R = 5.35m
Now we calculate the center of the orbit as:
rc = r1 + R(i) = (5.8+5.35)(i) + 5.6(j) = [11.15(i) + 5.6(j)] m
Answer:
The cattle train´s average speed was 10 km/h.
Explanation:
Hi there!
The traveled distance of the trains can be calculated using this equation:
d = v · t
Where:
d = traveled distance.
v = velocity of the train.
t = time.
The diesel train travels 4 hours at 45 km/h, then, the traveled distance will be:
d = 45 km/h · 4 h = 180 km
Because the diesel train catches the cattle train after traveling 180 km, this will also be the distance traveled by the cattle train. But it took the cattle train (14 h + 4 h) 18 hours to travel that distance. Then, using the equation of distance:
d = v · t
180 km = v · 18 h
180 km/ 18 h = v
10 km /h = v
The cattle train´s average speed was 10 km/h
Have a nice day!
I is just the uncertainty over the actual number multiplied by 100.
example:
36.1( +/- 0.1)
The percentage of the uncertainty here is 0.1/36.1x 100=0.3%
Answer:
Explanation:
V₀ = 0 m/s
V = 41 m/s
S = 480 m
___________
a - ?
Distance traveled:
S = (V² - V₀²) / (2*a)
Acceleration :
a = (V² - V₀²) / (2*S)
a = (41² - 0²) / (2*480) = 1.75 m/s²
