Answer:
<h2>2.6</h2>
Step-by-step explanation:
To solve this, we need to use the Pythagorean theorem to solve this.
The way to solve is by solving for AD by using triangle CAD and then using that result to solve for BD.
3.4² + b² = 6.5²
11.56 + b² = 42.25
42.25 - 11.56 = b²
b = √30.69
b = 5.53985559 or about 5.5
4.9² + b² = 5.5²
24.01 + b² = 30.69
30.69 - 24.01 = 6.68
b = √6.68
b = 2.58456959666 or about 2.6
<h2>EDIT: the other user is incorrect, here's why</h2>
3.4 + 4.5 = 7.9
6.5² + 4.9² = 7.9²
66.26 doesn't equal 62.41
Answer:
6 ft
Step-by-step explanation:
Step-by-step explanation:
mL = Undefined
mM = ?
mL × mM = -1
mM = -1 ÷ mL
mM = -1/mL
mM = -1/Undefined
mM = -1/(1/0)
mM = (-1 × 0)/1
mM = 0
Slope of line m is 0
Option → C
Answer:
a)= 2
b) 6.324
c) P= 0.1217
Step-by-step explanation:
a) The mean of the sampling distribution of X`1- X`2 denoted by ux`-x` = u1-u2 is equal to the difference between population means i.e = 2 ( given in the question)
b) The standard deviation of the sampling distribution of X`1- X`2 ( standard error of X`1- X`2) denoted by σ_X`1- X`2 is given by
σ_X`1- X`2 = √σ²/n1 +σ²/n2
Var ( X`1- X`2) = Var X`1 + Var X`2 = σ²/n1 +σ²/n2
so
σ_X`1- X`2 =√20 +20 = 6.324
if the populations are normal the sampling distribution X`1- X`2 , regardless of sample sizes , will be normal with mean u1-u2 and variance σ²/n1 +σ²/n2.
Where as Z is normally distributed with mean zero and unit variance.
If we take X`1- X`2= 0 and u1-u2= 2 and standard deviation of the sampling distribution = 6.324 then
Z= 0-2/ 6.342= -0.31625
P(-0.31625<z<0)= 0.1217
The probability would be 0.1217
