3 years ago

WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

SashulF [63]3 years ago

5 0

Answer:

x^2+6x+3=0

(X+3)^2-9+3=0

since (x+3)^2>=0 for any real value of x

at vertex

(X+3)^2=0

X=-3

i.e y=0-9+3=-6

vertex (-3,-6)

at y intercept x=0

y=3

x^2 coefficient is positive

therefore this is a concave up graph

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