Question

WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

Answer:

x^2+6x+3=0

(X+3)^2-9+3=0

since (x+3)^2>=0 for any real value of x

at vertex

(X+3)^2=0

X=-3

i.e y=0-9+3=-6

vertex (-3,-6)

at y intercept x=0

y=3

x^2 coefficient is positive

therefore this is a concave up graph