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3 years ago

How many 1 by 1/4 by 1 prisms fit inside by the 1 by 1 by 1 unit cube?

Mathematics

2 answers:

DochEvi [55]3 years ago

7 0

4 prisms can fit inside that one cube

Ludmilka [50]3 years ago

5 0

Answer:

Step-by-step explanation:

i took the test on edge :)

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PLEASE HELP DUE NOW!!!<br> WILL MARK BRAINLIEST!!!

Ulleksa [173]

Answer: -10, 10

Step-by-step explanation:

first lets add the two equations. add the x's, add the y's, add the constants on the right.

we get

0x - 1y = -10

so then divide --10 by -1 because we do the opposite operations to both sides

and we get y = 10

now substitute y = 10 into the first equation

-10x - 9(10) = 10

and then we get -10x - 90 = 10

now add 90 to both sides

-10x = 100

divide 100 by -10

x = -10

y = 10

checks out

EPIC. STAY EPIC AND AWESOME FRIEND.

3 0

2 years ago

HELP <br> 4 - x = 3x - 8 + 2x

USPshnik [31]

The answer is x=2 :) ✨

Hope it helps

6 0

2 years ago

PLzzzzzzz helppppppppp!!!

fomenos

5. y = -3 x - 8

6. y = - 1/2 x + 1

7 0

2 years ago

What is the domain of

Vsevolod [243]

The domain of what??

8 0

3 years ago

Read 2 more answers

Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3

Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

$f(x)=x^4-2ax^3+ax^2- x+k$

and

$f(-1)=3$

Answer:

$k = -2$ and $a=1$

Step-by-step explanation:

Given

$f(x)=x^4-2ax^3+ax^2- x+k$

$Factor:\ x - 4$

$f(-1)=3$

Required

Find a and k

For $f(-1)=3$

Substitute -1 for x

$f(x)=x^4-2ax^3+ax^2- x+k$

$f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k$

$f(-1) = 1 - 2a *-1 + a*1 +1 + k$

$f(-1) = 1 +2a + a +1 + k$

$f(-1) = 2 +3a + k$

Substitute 3 for f(-1)

$3 = 2 +3a + k$

Collect Like Terms

$3 - 2 = 3a + k$

$1 = 3a + k$

Also:

If $x - 2$ is a factor, then

$f(2) = 0$

Substitute 2 for x and 0 for f(x)

$f(x)=x^4-2ax^3+ax^2- x+k$

$0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k$

$0 = 16 - 2a * 8 + a * 4 - 2 + k$

$0 = 16 - 16a + 4a - 2 + k$

$0 = 16 - 12a - 2 + k$

Collect Like Terms

$2 - 16 = - 12a + k$

$-14 = k - 12a$

$k = 12a - 14$

Substitute 12a - 14 for k in $1 = 3a + k$

$1 = 3a + 12a - 14$

$1 = 15a - 14$

Collect Like Terms

$15a = 1 + 14$

$15a = 15$

Solve for a

$a = \frac{15}{15}$

$a=1$

Substitute 1 for a in $k = 12a - 14$

$k = 12 * 1 - 14$

$k = 12 - 14$

$k = -2$

3 0

2 years ago