Answer:
The correct answer is D.
Step-by-step explanation:
Given:
General equation of second degree
x² + y² + 14 x + 2 y + 14 = 0
We must transform given equation to the canonical form from which we will read requested data.
The canonical form of the circle equation is:
(x - p)² + (y - q)² = r²
Where p and q are the coordinates of the center of the circle and r are radius. (p,q) = (x,y)
x² + 2 · x ·7 + 7² - 7² + y² + 2 · y · 1 + 1 - 1 + 14 = (x+7)² + (y+1) - 49 - 1 + 14 = 0
(x + 7)² + (y + 1)² = 36
We see that p = - 7 , q = - 1 and r = 6
God with you!!!
Answer:
the answer is 52.
Step-by-step explanation:
You have to do [(6+6+2)*(3)] + [(2)*(5)] to get your answer.
(6+6+2)=14
14*3=42
2*5=10
10+42=52
When we are looking for the mid point, we are looking for a point that is an equal distance from point R and S.
Since the x value has no change, we can ignore it.
For the y value, we want to simply find the difference between the points (7 - 1 = 6) and then divide that value by 2 (6 / 2 = 3).
You can then subtract that value from the higher Y value, where you will get 4.
Leaving you with the coordinate (3,4)
Hope this helped. There are definitely more ways you could find to solve this, but this works best for this problem.
