Your question has been heard loud and clear.
2^0= 1
5^1= 5
4^3=64
2^0+5^1+4^3/7= 1+5+64/7 = 6+64/7= 15.14
So , 2^0+5^1+4^3/7 = 15.14
Thank you
Answer:
C
Step-by-step explanation:
most of the dots are along the line C
Answer: 
Step-by-step explanation:
Let be "x" the original volume of the solution (in milliliters) before the acid was added and "y" the volume of the solution (in milliliters) after the addition of the acid.
Set up a system of equations:
Applying the Substitution Method, you can substitute the second equation into the first equation and then solve for "x":
30 %
3/10 * 10 = 30/100
30/100= 30%
Answer:
-√(1 - 2x) + C
Step-by-step explanation:
1/√(1-2x)
We want to integrate it. Thus;
∫1/√(1 - 2x) dx
Let u = 1 - 2x
Thus;
du/dx = -2
Thus, dx = -½du
Thus,we now have;
-½∫1/√(u) du
By application of power rule, we will now have;
-½∫1/√(u) du = -√(u) + C
Plugging in the value of u, we will have;
-√(1 - 2x) + C
