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serious [3.7K]
3 years ago
15

Which expression is a factor of the quadratic 6x^2-11x-35? 2x-7, 2x-5, 2x+7, 2x+5

Mathematics
2 answers:
vovangra [49]3 years ago
8 0

1. Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

deff fn [24]3 years ago
8 0

Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

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4 raised to power two minus 8u minus 9=0​
coldgirl [10]

Answer:

x can be 3, -3, i, or -i.

Step-by-step explanation:

If you can't find the factoring by looking at this, simplify the equation.

let  

x

2

=

y

to make things easier to see

Now we have  

y

2

−

8

y

−

9

=

0

See it now?

We can factor into  

(

y

−

9

)

(

y

+

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)

Now substitute back in  

x

2

for  

y

.

(

x

2

−

9

)

(

x

2

+

1

)

Since  

(

x

2

−

9

)

is a difference of two squares,

(

x

−

3

)

(

x

+

3

)

Now we have  

(

x

−

3

)

(

x

+

3

)

(

x

2

+

1

)

x can be 3, -3 for the first two parts

x

2

+

1

=

0

can become  

x

2

=

−

1

Taking the positive and negative root means  

x

=

±

√

−

1

Thus  

x

=

±

i

in addition to 3 and -3.

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