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serious [3.7K]
3 years ago
15

Which expression is a factor of the quadratic 6x^2-11x-35? 2x-7, 2x-5, 2x+7, 2x+5

Mathematics
2 answers:
vovangra [49]3 years ago
8 0

1. Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

deff fn [24]3 years ago
8 0

Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

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Which of the following are solutions to the quadratic equation? Check all that
Troyanec [42]

Answer:

x = 1/3 or -2

Step-by-step explanation:

2x^2 + 7x - 2 = - x^2 + 2x

3x^2 + 5x - 2 = 0 (use factoring)

(3x − 1)(x + 2) = 0

3x - 1 = 0    OR     x + 2 = 0

3x = 1                   x = - 2

x = 1/3

Can you mark as brainliest? Hope it helps by the way!

3 0
3 years ago
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Which statement best explains why the graphed relation is not a function?
timurjin [86]
C. A function can only have one y value for an x value
5 0
3 years ago
Find y: y − 4 = 6<br> A. 4<br> B. 10<br> C. 2<br> D. 6
aleksandrvk [35]

Answer:

Correct Answer is B

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y-4=6

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7 0
2 years ago
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Please help!<br> Hard math.
Reil [10]

Answer:

the value of digit 3 in 156.32 =

3 x 0.1 = 0.3


The value of digit 3 in 13 =

3 x 1 = 3

3/0.3=10 times

The value of digit 3 in 13 is 10 ten times the value of digit 3 in 156.32

As long as the (digit in ones/single digit) of a number is equal to 3

The value of digit 3 of it is always 10 ten times the value of digit 3 in 156.32


5 0
2 years ago
Every autumn, the North American Monarch
Stolb23 [73]

Part A

The equation is d = 50t

This is because the slope of 50 represents how many miles per day the butterflies cover (on average). The y intercept is 0 to indicate that 0 miles have been traveled initially.

You can think of this as the equation y = 50x

If t = 1, then d = 50t = 50*1 = 50 miles have been covered

If t = 2, then d = 50t = 50*2 = 100 miles have been covered

And so on.

==========================================================

Part B

You'll have these values in the bottom row (in the order presented): 50, 100, 150, 200, 250

You can plug in the values t = 1, t = 2, t = 3, t = 4 and t = 5 into d = 50t to find those answers in bold.

Or you could add on 50 each time to generate each new value. We start at 50 since t = 1 corresponds to d = 50.

==========================================================

Part C

You can keep the pattern of 50,100,150, ... going until you reach 2500. Then note the t value that pairs with d = 2500

In my opinion, that's the slower method.

The quicker method is to plug d = 2500 into the equation for part A, and then solve for t.

d = 50t

2500 = 50t

50t = 2500

50t/50 = 2500/50 ....... divide both sides by 50

t = 50

It will take 50 days for the average distance traveled to be 2500 miles.

6 0
3 years ago
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