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3 years ago

Which expression is a factor of the quadratic 6x^2-11x-35? 2x-7, 2x-5, 2x+7, 2x+5

Mathematics

2 answers:

vovangra [49]3 years ago

8 0

1. Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

deff fn [24]3 years ago

8 0

Split the second term in 6x^2 - 11x - 35 into two terms

6x^2 + 10x - 21x - 35

2. Factor out common terms in the first two terms, then in the last two terms

2x(3x + 5) - 7(3x + 5)

3. Factor out the common term 3x + 5

(2x - 7)

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Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle

balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0

3 years ago

Angela ordered 2 glass paperweights. The volume of each paperweight is 5 cubic inches, and the density of the glass is 1.5 ounce

Katarina [22]

Answer:

$(2\times 5)\times 1.5$

Step-by-step explanation:

Since, according to associative property of multiplication,

a(bc) = (ab)c,

Where a, b and c are any real numbers,

Here, the given expression,

2 × ( 5 × 1.5 ),

By applying the associative property of multiplication,

( 2 × 5 ) × 1.5,

Hence, the appropriate expression in the first box is '(2×5)'

And, the appropriate number in the second box is '1.5'.

8 0

3 years ago

In the graphic below,

sukhopar [10]

The external angle is suplementary to the internal angle close to it. We also know that the sum of all the internal angles of the triangle are equal to 180 degrees, this means that the angle "a" is suplementary to the sum of the angles "b" and "c". Through this logic, we can conclude that since: