All categories

3 years ago

Help please!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Anna71 [15]3 years ago

5 0

Answer:

the answer is 9.5

Step-by-step explanation:

Veronika [31]3 years ago

3 0

Answer:

I think it's C. 9.5

Hope this Helps!

You might be interested in

Simplify<br><br> 1/4 (-12+4/3)

garri49 [273]

Decimal form: -2.6666..
Fraction form: -2 2/3

8 0

3 years ago

What is the exact answer is betwwen 6×7,381

Alex Ar [27]

You can do:
6x7000 then
6x300 then
6x80 then
6x1 then
you add all the product.
the answer 4,4286

5 0

3 years ago

Read 2 more answers

Determine the surface area of the cylinder below.

Dahasolnce [82]

Answer:

Step-by-step explanation:

We will need calculate the area of the top, the base and sides.

Area of the top=πr²

Area of the base=πr²

Area of the side: 2πrh

Surface area of a cylinder: area of the top + area of the base +area of the side

Surface area of a cylinder=πr²+πr²+2πrh=2πr²+2πrh=2πr(r+h)

Data:

r=1.5 m

h=1.5 m

Surface area of this cylinder=2π(1.5m)(1.5 m+1.5 m)=3π m*(3 m)=9π m².

6 0

3 years ago

What are two numbers that add to make 36 with one of the numbers be exactly twice the other

Tema [17]

To solve, set an equation:
First Number: x
Second Number: 2x

x+2x=36
3x=36
divide both sides by 3
x=13

First Number: (x) 12
Second Number: (2x) 24

Answers: 12 and 24

3 0

3 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

3 years ago