Answer:
y = x^2 + 8x + 16
y = x + 6
x^2 + 8x + 16 = x + 6
x^2 + 7x + 10= 0
(x + 5)(x+2) = 0
x = -5
x = -2
y = (-5)^2 + 8(-5) + 16
y = 25 - 40 + 16
y = 41 - 40
y = 1
y = -5 + 6= 1
y= (-2)^2 + 8(-2) + 16
y = 4 - 16 + 16 = 4 + 0 = 4
y = -2 + 6 = 4
Point of intersection: (-2, 4)
Step-by-step explanation:
N+d=34
.05n+.10d=2.60
Solve by substitution
n=34-d
.05(34-d)+.10d=2.60
1.7-.05d+.10d=2.60
.05d=.90
d=18 dimes
18+n=34
n=16 nickles
If the sides were 2 and 3 then using Pythagoras the diagonal would be sr(2^2 + 3^2) = sr(13)
The actual diagonal is 8 inches so the sides need to be scaled by 8/sr(13)
The screen area will be 2 x 8/sr(13) x 3 x 8/sr(13) = 29.539....
Rounded to nearest sq.inch this is 30 sq.inch
Answer:
43
Step-by-step explanation:
Answer:
<em><u>the </u></em><em><u>answer </u></em><em><u>is </u></em><em><u>5</u></em><em><u> </u></em>
<em><u>HEY!</u></em><em><u>!</u></em><em><u>^</u></em><em><u>^</u></em>
<em><u>have </u></em><em><u>a </u></em><em><u>good</u></em><em><u> day</u></em><em><u>!</u></em><em><u>!</u></em><em><u>^</u></em><em><u>^</u></em>
<em><u>thank</u></em><em><u> me</u></em><em><u> later</u></em>
<em><u>carryonlearing</u></em>
