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Wewaii [24]
3 years ago
9

A swimming pool has a radius of 8 feet and a height of 5 feet. The swimming pool is shaped like a cylinder. What is the volume o

f the swimming pool, to the nearest cubic foot? Use 3.14 for π
Mathematics
2 answers:
Eva8 [605]3 years ago
4 0

Answer:

1005cm³

Step-by-step explanation:

8² x 3.14 = 200.96 = surface area of face

200.96 x 5 = 1004.8 = 1005cm³

IrinaK [193]3 years ago
4 0

Answer:

Volume = 1004.8ft*3

However with full measure π it is slightly higher on calculator.

1005.31ft^3

Step-by-step explanation:

(V):3.14 x 8^2=200.96 x 5

(V):200.96 x 5 = 1004.8

Volume =1004.8ft^3

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Consider the figure. Determine the value of y.​
slava [35]

Answer:

47+ y = 180          (linear pair)

y = 133

6 0
3 years ago
PLEASE HELP!!!!! How many 4-digit numbers divisible by 5, all of the digits of which are even, are there?
saul85 [17]

Answer:

I assume you know Arithmetic Progression .

so, we have to find the first and last 4-digit number divisible by 5

first = 1000 ,  last =  9990

we have a formula,   a_{n} = a + (n-1)d

here, a_{n} is the last 4-digit number divisible by 5.

n is the number of 4-digit even numbers divisible by 5

d is the common difference between the numbers, which is 10 in this case

a is the first 4-digit number divisible by 5

9990 = 1000 + (n-1)*10

899 = n-1

n = 900

Hence, there are 900 4-digit even numbers divisible by 5

7 0
3 years ago
Three stamps can be attached to each other in various ways.how many ways might three stamps be attached?
ivanzaharov [21]
Let's call the stamps A, B, and C. They can each be used only once. I assume all 3 must be used in each possible arrangement.
There are two ways to solve this. We can list each possible arrangement of stamps, or we can plug in the numbers to a formula. 
Let's find all possible arrangements first. We can easily start spouting out possible arrangements of the 3 stamps, but to make sure we find them all, let's go in alphabetical order. First, let's look at the arrangements that start with A:
ABC
ACB
There are no other ways to arrange 3 stamps with the first stamp being A. Let's look at the ways to arrange them starting with B:
BAC
BCA
Try finding the arrangements that start with C:
C_ _
C_ _
Or we can try a little formula; y×(y-1)×(y-2)×(y-3)...until the (y-x) = 1 where y=the number of items.
In this case there are 3 stamps, so y=3, and the formula looks like this: 3×(3-1)×(3-2).
Confused? Let me explain why it works.
There are 3 possibilities for the first stamp: A, B, or C. 
There are 2 possibilities for the second space: The two stamps that are not in the first space.
There is 1 possibility for the third space: the stamp not used in the first or second space. 
So the number of possibilities, in this case, is 3×2×1.
We can see that the number of ways that 3 stamps can be attached is the same regardless of method used.


8 0
3 years ago
Find the general solution of x'1 = 3x1 - x2 + et, x'2 = x1.
Ann [662]
Note that if {x_2}'=x_1, then {x_2}''={x_1}', and so we can collapse the system of ODEs into a linear ODE:

{x_2}''=3{x_2}'-x_2+e^t
{x_2}''-3{x_2}'+x_2=e^t

which is a pretty standard linear ODE with constant coefficients. We have characteristic equation

r^2-3r+1=\left(r-\dfrac{3+\sqrt5}2\right)\left(r+\dfrac{3+\sqrt5}2\right)=0

so that the characteristic solution is

{x_2}_C=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}

Now let's suppose the particular solution is {x_2}_p=ae^t. Then

{x_2}_p={{x_2}_p}'={{x_2}_p}''=ae^t

and so

ae^t-3ae^t+ae^t=-ae^t=e^t\implies a=-1

Thus the general solution for x_2 is

x_2=C_1e^{(3+\sqrt5)/2\,t}+C_2e^{-(3+\sqrt5)/2\,t}-e^t

and you can find the solution x_1 by simply differentiating x_2.
7 0
3 years ago
Solve the proportion 18/2 = t/7
Firlakuza [10]

Answer:

t=63

Step-by-step explanation:

2t = 126

t=63

3 0
2 years ago
Read 2 more answers
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