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Liono4ka [1.6K]
4 years ago
11

Consider the two triangles.

Mathematics
1 answer:
Masja [62]4 years ago
3 0
For the answer to the question above, you just simply use the Pythagoras theorem to find the 3rd length, a^2+b^2=c^2.
E.g 15^2+20^2= length of hypotenuse^2 
225+400=c^2
625=c^2
25=c
Which makes no. <span>1. AB = 25 and HG = 15 the answer. I hope this helps</span>
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Step-by-step explanation:

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lilavasa [31]

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Step-by-step explanation:

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3 years ago
1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both
Alja [10]

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}

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3 years ago
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Butoxors [25]

So what’s the question? What are we trying to find?

4 0
4 years ago
Help me with this please
Rufina [12.5K]

Answer: (2,7)

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1 + 3 / 2 = 2

5 + 9 / 2 = 7

3 0
3 years ago
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