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11Alexandr11 [23.1K]
2 years ago
5

an office supply company is shipping a case of wooden pencils. there are 64 boxes of pencils in the case. if each box of pencils

weighs 2.5 ounces, what is the eight, in pounds, of the case of wooden pencils.
Mathematics
2 answers:
bearhunter [10]2 years ago
7 0

Answer:

Since there are 64 boxes you would multiply 64 and 2.5. After you get that answer (which will be 160.0) (which is technically 160) divide that by 16. And your answer will be 10.

Equation:

64 x 2.5 = 160.0 divided by 16 = 10

Levart [38]2 years ago
3 0
<span>64 boxes of pencils per case x 2.5 ounces per box ÷16 ounces per pound = pounds per case</span>
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zavuch27 [327]

Given:

The parent absolute function is

f(x)=|x|

To find:

The new function if the parent function is translated up by 5 units and vertically stretched by a factor of 3.

Solution:

The translation is defined as

g(x)=kf(x+a)+b                .... (1)

Where, k is stretch factor, a is horizontal shift and b is vertical shift.

If 0<k<1, then the graph compressed vertically by factor k and if k>1, then the graph stretch vertically by factor k.

If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.

If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.

Parent function is translated up by 5 units. So, b=5

It is vertically stretched by a factor of 3. So, k=3.

There is no horizontal shift. So, a=0.

Now, putting k=3, a=0 and b=5 in (1), we get

g(x)=3f(x+0)+5

g(x)=3f(x)+5

g(x)=3|x|+5       [\because f(x)=|x|]

Therefore, the correct option is D.

5 0
3 years ago
7. (05.02 MC)
Diano4ka-milaya [45]

Considering the Central Limit Theorem, we have that:

a) The probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.

b) The probability can be calculated, as the sample size is greater than 30.

<h3>What does the Central Limit Theorem state?</h3>

It states that the sampling distribution of sample means of size n is approximately normal has standard deviation s = \frac{\sigma}{\sqrt{n}}, as long as the underlying distribution is normal or the sample size is greater than 30.

In this problem, the underlying distribution is skewed right, that is, not normal, hence:

  • For item a, the probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
  • For item b, the probability can be calculated, as the sample size is greater than 30.

More can be learned about the Central Limit Theorem at brainly.com/question/16695444

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8 0
2 years ago
I know its easy but i suck at math pls help
e-lub [12.9K]

Answer:

-6.8125

Step-by-step explanation:

Convert 13/16 to a decimal.

Write -6 down

You get -6.8125.

Hope this helps! If it does, please mark me brainliest, and press thank you to help me. Thank you! ;)

Good luck on whatever you are doing.

3 0
3 years ago
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The diameter of bushings turned out by a manufacturing process is a normally distributed random variable with a mean of 4.035 mm
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B) 4.035 +/- 1.96 x sqrt( 0.005/sqrt(25))

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enyata [817]

Answer:

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6 0
3 years ago
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