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Vesna [10]
3 years ago
7

Estimation of 375+ 147

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
3 0
Well round them so the estimation would be 520,(for hundred) and 520 (for tens)

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Solve for q. -5(3-q) +4=5q-11
soldier1979 [14.2K]

Perform the indicated multiplication first:  -15 + 5q + 4 = 5q - 11

Note that 5q appears on both sides of this equation.  Cancelling, we get :

-11 = -11.  This is always true.  Thus, -5(3-q) +4=5q-11 is true for all q.

4 0
3 years ago
A decent-sized square plot of land in town is one acre. If Mr. Pearson wants to play football with his son Connor, then how far
sammy [17]
One acre of land is equal to 4046.86 sq.m.
To know how far they can throw the ball from corner to corner can be interpreted in two ways: throwing the ball diagonally across the field or throwing the ball horizontally across the field. For the first question, since the field is a square, you can use the equation Diagonal of Square = A x sq.root of 2.

In this case, the answer would be 89.97 m.

If the ball is thrown horizontally across the field, then you would only need to know the length of one side of the square, which is the square root of the area. Doing this would give you the answer 63.61 m.
4 0
3 years ago
Read 2 more answers
Help please!!! I’ll mark u as brainliest
sergeinik [125]

Answer:

Answer is below

Step-by-step explanation:

Yes, the graph would still be a function, but a different function than if the values were all different. This would cause two of the values to be the same and have no slope on the line. Before, the function was quadratic, but now it would be quadratic until the two values are equal.

7 0
4 years ago
A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
Evaluate the following expression when x = 3 and y = 4:
SpyIntel [72]
Not 100% sure but I think that it is 14.6
4 0
3 years ago
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