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<u>Given</u>:
Given that ABC is a right triangle.
The length of AB is 7 units.
The measure of ∠A is 65°
We need to determine the length of AC
<u>Length of AC:</u>
The length of AC can be determined using the trigonometric ratio.
Thus, we have;
Where the value of 
is 65° and the side adjacent to the angle is AC and the side hypotenuse to the angle is AB.
Substituting the values, we have;
Substituting AB = 7, we have;
Multiplying both sides by 7, we get;
Rounding off to the nearest hundredth, we get;
Thus, the length of AC is 2.96 units.
30% of the 30 marbles is nine and 9-30 = 21 so your answer is 21
Let's examine the given function first:
f(x) = x^2 + 1 is the same as f(x) = 1(x-0)^2 + 1.
The vertex of the graph of this function is at (0, 1).
Let x=0 to find the y-intercept: f(0)=0^2+1 = 1; y-int. is at (0,1) (which happens to be the vertex also)
Comparing f(x) = x^2 + 1 to y = x^2, we see that the only difference is that f(x) has a vertical offset of 1. So: Graph y=x^2. Then translate the whole graph UP by 1 unit. That's it. Note (again) that the vertex will be at (0,1), and (0,1) is also the y-intercept.
C i thinks, but im not even sure so
